Answer:
Two
Step-by-step explanation:
x² + 4 = 4x + 1
x² - 4x + 3 = 0
x² - 3x - x + 3 = 0
x(x - 3) - (x - 3) = 0
(x - 3)(x - 1) = 0
x = 1, 3
y = 4(1) + 1 = 5
y = 4(3) + 1 = 13
Two solutions: (1,5) (3,13)
Answer:
Answer is ![\frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D)
Step-by-step explanation:
To find the interval of x. Use our equations to equal each other.
![-x^2+2x=y,y=0](https://tex.z-dn.net/?f=-x%5E2%2B2x%3Dy%2Cy%3D0)
![-x^2+2x=0\\-x(x-2)=0\\-x=0 , (x-2)=0\\x=0 ,2](https://tex.z-dn.net/?f=-x%5E2%2B2x%3D0%5C%5C-x%28x-2%29%3D0%5C%5C-x%3D0%20%2C%20%28x-2%29%3D0%5C%5Cx%3D0%20%2C2)
![\int\limits^2_0 {-x^2+2x} \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E2_0%20%7B-x%5E2%2B2x%7D%20%5C%2C%20dx)
Integrate.
![\frac{-x^3}{3}+x^2\\(\frac{-2^3}{3}+2^2)-[\frac{-0^3}{3}+0^2]\\-\frac{8}{3} +4-0\\-\frac{8}{3}+\frac{12}{3} =4/3](https://tex.z-dn.net/?f=%5Cfrac%7B-x%5E3%7D%7B3%7D%2Bx%5E2%5C%5C%28%5Cfrac%7B-2%5E3%7D%7B3%7D%2B2%5E2%29-%5B%5Cfrac%7B-0%5E3%7D%7B3%7D%2B0%5E2%5D%5C%5C-%5Cfrac%7B8%7D%7B3%7D%20%2B4-0%5C%5C-%5Cfrac%7B8%7D%7B3%7D%2B%5Cfrac%7B12%7D%7B3%7D%20%20%3D4%2F3)
Using Desmos I have Graphs of both of the equations you have provided. The problem asks us to find the shaded region between those curves/equations.
Proof Check your interval of x.
Answer:
$88.00
Step-by-step explanation:
66=3/4x
66/.75=66*4/3=88
The absolute value of -54 is 54.
So The answer is A