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PolarNik [594]
3 years ago
13

In parallelogram DEFG, DH = x + 5, HF = 2y, GH = 3x – 1, and HE = 5y + 4. Find the values of x and y. x = 21, y = 20 x = 35, y =

20 x = 21, y = 37 x = 20, y = 35
Mathematics
1 answer:
Natali5045456 [20]3 years ago
4 0
The answer is:
x=35, y=20
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A 28ft ladder leans against a wall so that the base of the ladder is 5ft away from the base of the wall. How far up the wall doe
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Answer:

the top of the ladder is 27.5ft above the ground.

Step-by-step explanation:

The ladder makes an angle, θ with the ground thus forming a right angle triangle with the wall of the house.

The length of the ladder represents the hypotenuse of the right angle triangle.

The ground distance from the base of the wall to the foot of the ladder represents the adjacent side of the right angle triangle.

Therefore, to determine how high up is the top of the ladder on the wall, x, we would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

28² = x² + 5²

784 = x² + 25

x² = 784 - 25 = 759

x = √759 = 27.5ft

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What is the measure of angle VYZ
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Answer:

\boxed{\sf C. \ 161 ^{ \circ}}

Step-by-step explanation:

<em>Opposite angles are also congruent angles, meaning they are equal or have the same measurement.</em>

\sf \implies \angle VYZ = \angle WYT \\  \\  \sf \implies(8x  + 1) ^{ \circ}  = (9x  - 19)^{ \circ}  \\  \\  \sf \implies 8x^{ \circ}  + 1^{ \circ}  = 9x^{ \circ}  - 19^{ \circ}  \\  \\  \sf \implies 8x^{ \circ}  - 9x^{ \circ}   + 1^{ \circ} =  - 19^{ \circ}  \\  \\  \sf \implies  - x^{ \circ}   =  - 19^{ \circ}   -   1^{ \circ}  \\  \\  \sf \implies  \cancel{ -} x^{ \circ}   =   \cancel{- }20^{ \circ}    \\  \\  \sf \implies   x^{ \circ}   =  20^{ \circ}

\therefore

\sf \implies \angle VYZ =(8x + 1) ^{ \circ}  \\  \\  \sf \implies \angle VYZ =(8  \times 20 + 1) ^{ \circ}  \\  \\  \sf \implies \angle VYZ =( 160+ 1) ^{ \circ}  \\  \\  \sf \implies \angle VYZ =161 ^{ \circ}

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