Ask question

Ask question

All categories

andrew-mc [135]

3 years ago

6

The manager of a neighborhood plant nursery measured the height of every tree on the lot. The mean height of the trees was 75 in

ches and the median height was 62 inches. What was the shape of the distribution?
symmetric
roughly symmetric
skewed to the left
skewed to the right

1 answer:

zloy xaker [14]3 years ago

4 0

Answer: D. skewed to the right

Step-by-step explanation:

just took it

You might be interested in

Vertical stretch by a factor of 3 and a reflection

atroni [7]

Vertical stretch by a factor of 3 and a reflection over x-axis is g(x)= -3|x|

7 0

3 years ago

It took 7 hours to mow 4 lawns. How many lawns can I mow in 35 hours? Confused.. Please Check!!!

blondinia [14]

<u>7</u> <u>35</u> 4x35/7= 20 lawns<u>
</u>4 x<u>
</u>

6 0

3 years ago

Determine all prime numbers a, b and c for which the expression a ^ 2 + b ^ 2 + c ^ 2 - 1 is a perfect square .

kogti [31]

Answer:

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Step-by-step explanation:

From Algebra we know that a second order polynomial is a perfect square if and only if $(x+y)^{2} = x^{2} + 2\cdot x\cdot y + y^{2}$ . From statement, we must fulfill the following identity:

$a^{2} + b^{2} + c^{2} - 1 = x^{2} + 2\cdot x\cdot y + y^{2}$

By Associative and Commutative properties, we can reorganize the expression as follows:

$a^{2} + (b^{2}-1) + c^{2} = x^{2} + 2\cdot x \cdot y + y^{2}$ (1)

Then, we have the following system of equations:

$x = a$ (2)

$(b^{2}-1) = 2\cdot x\cdot y$ (3)

$y = c$ (4)

By (2) and (4) in (3), we have the following expression:

$(b^{2} - 1) = 2\cdot a \cdot c$

$b^{2} = 1 + 2\cdot a \cdot c$

$b = \sqrt{1 + 2\cdot a\cdot c}$

From Number Theory, we remember that a number is prime if and only if is divisible both by 1 and by itself. Then, $a, b, c > 1$ . If $a$ , $b$ and $c$ are prime numbers, then $2\cdot a\cdot c$ must be an even composite number, which means that $a$ and $c$ can be either both odd numbers or a even number and a odd number. In the family of prime numbers, the only even number is 2.

In addition, $b$ must be a natural number, which means that:

$1 + 2\cdot a\cdot c \ge 4$

$2\cdot a \cdot c \ge 3$

$a\cdot c \ge \frac{3}{2}$

But the lowest possible product made by two prime numbers is $2^{2} = 4$ . Hence, $a\cdot c \ge 4$ .

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Example: $a = 2$ , $c = 2$

$b = \sqrt{1 + 2\cdot (2)\cdot (2)}$

$b = 3$

4 0

3 years ago

What function is the inverse of the exponential function y = (1.5)x?

vagabundo [1.1K]

Correct question is;

What function is the inverse of the exponential function y = 1.5^(x)?

Answer:

y = log_1.5_x

Step-by-step explanation:

The inverse of exponential functions is usually written in form of logarithm.

For example inverse of y = p^(x) will be written as; y = log_p_(x)

Similarly applying this same pattern to our exponential function y = 1.5^(x), we have the inverse as;

y = log_1.5_x

6 0

2 years ago

$9 for 6 pounds How much for 1 pound?

hram777 [196]

Answer:

1.50

Step-by-step explanation:

8 0

3 years ago