Answer:
Explanation:
<em>Given:</em>
Refractive index of prism μ = 1.5
Since the prism is equilateral,
Angle of prism A= 60°
<em>To find:</em>
Angel of incidence for which minimum deviation can occur(δm) ?
<em>Solution:</em>
We know that,
The refractive index, Angle of prism and angle of minimum deviation are correlated with formula,
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Where symbols have their usual meaning.
Substituting the value from given data in formula,
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Answer:
a) 390J
b) 322J
c) 68J
Explanation:
We need to calculate the power given by the battery. the power is given by:
Watts is J/s so:
The thermal energy in the wire is given by:
And the the dissipated thermal energy in the battery will be the remainig energy:
Using kinematic equation v=u+at......... 1.
v = final velocity = 0 m/s. u = initial velocity = 13.5 m/s.
a = -0.5 m/s².
Plug all the known values in 1 to find t
Kelvin is a base unit of temperature
scale from SI that defines as zero degree Kelvin (absolute zero). The absolute
zero is a hypothetical statement that all molecular movement stops because
there is no transient of energy for the molecules to move. When converting
temperature in degree Celsius to Kelvin, add 273. You are given 600K and you
are asked to find it in degrees Celsius.
T(K) = T(C) + 273
600 K = T(C) + 273
T(C) = 600 – 273
T(C) = 327 °C
<span>The answer is letter B.</span>
Answer:
Intensity of the transmitted radio wave is 5.406 x 10⁻⁶ W/m²
Explanation:
Given;
power of radio transmitter, P = 63.2 kW = 63200 W
distance of transmission, r = 30.5 km
Intensity of the transmitted radio wave is calculated as follows;
where;
I is the intensity of the transmitted radio wave
Substitute the given values and calculate the intensity of the transmitted radio wave;
Therefore, Intensity of the transmitted radio wave is 5.406 x 10⁻⁶ W/m²