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OleMash [197]
3 years ago
15

A toy remote control car drives in a circle (the controller is stuck). It makes 8 revolutions in 14

Physics
1 answer:
IceJOKER [234]3 years ago
7 0

Answer:

Period for 1 revolution is 1.75 seconds

Explanation:

given data

revolutions R = 8

time t = 14 seconds

to find out

What is the period

solution

we know that Period is the time per revolution

so here period formula that is express as

period = \frac{R}{t} = \frac{8}{14} = 0.57 revolution in one second

so in 1 revolution = \frac{1}{0.57} seconds

so in 1 revolution = 1.75 seconds

so period for 1 revolution is 1.75 seconds

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Compare convergent plate boundaries that have the same density to convergent plate boundaries with different densities.
andrey2020 [161]

Answer:

If the two plates are of equal density, they usually push up against each other, forming a mountain chain. If they are of unequal density, one plate usually sinks beneath the other in a subduction zone. Hope this helps!

Explanation:

4 0
4 years ago
To maximize the percentage of the power from the emf of a battery that is delivered to a device, what should the internal resist
Simora [160]

To maximize the power delivered to load, we should minimize the internal resistance which means option A is correct.

<h3>What is the relationship between the power and the internal resistance?</h3>

Power  can be  delivered to the internal resistance of a battery, but in a case whereby there is a decrease in the internal resistance will bring about the decrease in the  lost power  as well as the  increase in  the percentage of the power delivered to the device.

In this case, To maximize the power delivered to load, we should minimize the internal resistance

Therefore, Option A is correct.

Learn more about power on:

brainly.com/question/17086286

#SPJ4

3 0
2 years ago
The electrical loads in _____ circuits each have the same voltage drop, with equals the total applied voltage of the circuit.
Vesna [10]

Answer:

The electrical loads in parallel circuits each have the same voltage drop, with equals the total applied voltage of the circuit.

Explanation:

I did some research and the voltage drop across any branch of a parallel circuit is the same as the applied voltage.

3 0
3 years ago
A water trough is 12 feet long, and its cross section is an equilateral triangle with sides 2 feet long. Water is pumped into th
MAXImum [283]

Answer:

The water level rises at 11.76 ft^{2} /s

h=\sqrt{3/2} s let be h: height and s: side of an equilateral triangle

Explanation:

The picture shows a diagram of the situation, first we have to determine the height of the trough as follows:

With the Pytagorean Theorem we can find out that:

h^{2} =s^{2} -s^{2} /4 =\sqrt{3} /2 s

Then, the area of an equilateral triangle, as any triangle, is a half of its base times its height:

A=\frac{1}{2} hs=\frac{1}{2} \frac{\sqrt{3} }{2} s^{2} =\frac{\sqrt{3} }{4} s^{2}

Replacing values, we have:

A=1.73ft^{2}

That is the total area of the trough, but the problem specifies that it has been filled until 0.5 ft. Therefore, we have to find the cross section area of the water flow by substracting the total area minus the unfilled area of the trough:

h_{u}: height of the unfilled triangle\\s_{u} : side of the unfilled triangle\\A_{u}: area of the unfilled triangle\\h_{u}=\sqrt{3} -0.5 =1.23\\s_{u}= \frac{2}{\sqrt{3} } 1.23=1.42\\A_{u}=\frac{\sqrt{3} }{4} 1.42^{2} =0.87ft^{2} A_{u}

Then, the cross section area of water flow is

A_{s} =1.73ft^{2} -0.87ft^{2} =0.85ft^{2}

Finally, to determine the speed of water flow at this point we solve for v, the  flow formula:

Q: water flow\\v: speed\\Q=vA\\v=Q/A =\frac{10ft^{3}/s }{0.85ft^{2} } =11.76 \frac{ft^{2}}{s}

6 0
3 years ago
A solid steel column is 4.0 m long and 0.20 m in diameter. Young's modulus for this steel is 2.0 × 1011 N/m2. By what distance d
zzz [600]

Answer:

3.12 x 10^-5 m

Explanation:

Length of steel column, L = 4 m

diameter, d = 0.2 m

radius = half of diameter = 0.1 m

Young's modulus, Y = 2 x 10^11 N/m^2

Mass of truck, m = 5000 kg

Force, F = mass of truck x acceleration due to gravity

F = 5000 x 9.8 = 49000 N

Area of crossection of cable,

A =  \pi r^{2}=3.14\times\0.1\times0.1=0.0314m^{2}

Let ΔL be the shrink in length of cable, then by the formula of Young's modulus

Y=\frac{F\times L}{A\times\Delta L}

\Delta L = \frac{F\times L}{A\times Y}

\Delta L = \frac{49000\times 4}{0.0314\times 2\times10^{11}}

ΔL = 3.12 x 10^-5 m

Thus, the shrink in the length of cable is 3.12 x 10^-5 m.

8 0
3 years ago
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