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GREYUIT [131]
2 years ago
10

25 is what percent of 365

Mathematics
2 answers:
QveST [7]2 years ago
5 0
(25/365)x100=6.85 (3 s.f)
kondaur [170]2 years ago
3 0
\begin{array}{ccc}365&-&100\%\\25&-&x\%\end{array}\ \ \ |cross\ multiply\ both\ sides\\\\365\cdot x=25\cdot100\\365x=2500\ \ \ \ \ |divide\ both\ sides\ by\ 365\\\\x=\frac{2500}{365}\\\\x=\frac{2500:5}{365:5}=\frac{500}{73}=\boxed{6\frac{62}{73}\ (\%)\approx7\%}
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Let $f(x)$ be the real-valued function defined for all real $x$ except for $x = 0$ and $x = 1$ and satisfying the functional equ
Mademuasel [1]
We have to find the values of F.
In this case. F is unlikely to be a polynomial.
But the problem is, we can’t calculate the values of F directly.
There is no real value of x for which x = x−1 x because F isn’t defined at 0 or 1. so,
substituting x = 2.
F(2) + F(1/2) = 3.

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7 0
2 years ago
Add.<br><br> (6x3+3x2−2)+(x3−5x2−3)<br><br> Express the answer in standard form.
sergiy2304 [10]

Answer:

7x^3-2x^2-5

Step-by-step explanation:

We need to add the two terms.

(6x^3+3x^2-2)+(x^3-5x^2-3)

Solving,

Combine the like terms and adding those terms

(6x^3+3x^2-2)+(x^3-5x^2-3)\\=6x^3+3x^2-2+x^3-5x^2-3\\=6x^3+x^3+3x^2-5x^2-2-3\\=7x^3-2x^2-5

So, the answer is:

7x^3-2x^2-5

6 0
3 years ago
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