What is the answer to (u-v)/8v+(6u-3v)/8v

For each home run hit in a baseball game, a

nata0808 [166]

the answer is “c” i believe

8 0

3 years ago

1) A boat traveled 448 miles downstream and back. The trip downstream took 14 hours. The trip

Serhud [2]

Answer:B

I think we are in the same class lol

Step-by-step explanation:448 divided by 14= 32

448 divided by 16= 28

B=speed of boat in water

Y= Speed of current

B+y=32

B-y=28

32 + 28 =60

60 divided by 2 = 30

32 -30 =2

B=30

Y=2

Add my discord if you need more help Snapple#0141

6 0

3 years ago

If SV⊥RT, m∠RSU = (17x – 3)°, and m∠UST = (6x – 1)°, find TSV

goblinko [34]

Applying the linear pair theorem, the measure of angle TSV in the image given is: 86°.

<h3>How to Apply the Linear Pair Theorem?</h3>

Given the following angles in the image above:

Measure angle RSU = (17x - 3)°,

Measure angle UST = (6x – 1)°

To find the measure of angle TSV, we need to find the value of x in the given expressions as shown below:

m∠RSU + m∠UST = 180 degrees (linear pair]

Substitute the values

17x - 3 + 6x - 1 = 180

Solve for x

23x - 4 = 180

23x = 180 + 4

23x = 184

x = 8

m∠TSV = 180 - 2(m∠UST) [Linear Pair Theorem]

m∠TSV = 180 - 2(6x - 1)

Plug in the value of x

m∠TSV = 180 - 2(6(8) - 1)

m∠TSV = 86°

Therefore, applying the linear pair theorem, the measure of angle TSV in the image given is: 86°.

Learn more about the linear pair theorem on:

brainly.com/question/5598970

#SPJ1

6 0

1 year ago

The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi

inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

$\displaystyle\frac{dr}{dt} = -7\text{ inch per second}$

The volume is decreasing at a constant rate.

$\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}$

Instant radius = 99 inch

Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

$V = \displaystyle\frac{1}{3}\pi r^2 h$

Instant volume =

$525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}$

Differentiating with respect to t,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)$

Putting all the values, we get,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131$

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

3 0

3 years ago

5x - 9 = -8y - 3 what’s the x and y value of this equation

Feliz [49]

Answer:

$y= -\frac{5x}{8} +\frac{3}{4} \\$

$x= -\frac{8y}{5} +\frac{6}{5}$

Step-by-step explanation:

8 0

3 years ago