Quotient is the result of division. Assign a variable to the unknown number. Let's make it x. Write the statement as an equation.
x/5 - 10 = 3
solve for x
x/5 - 10 = 3
x/5 = 3 + 10
x/5 = 13
x = 5 × 13
x = 65
Answer:
Im going to guess k is the unknown
Step-by-step explanation:
7k-14=42
42+14=7k
56=7k
56/7=k
k=8
Answer:
1. t = 0.995 s
2. h = 15.92 ft
Step-by-step explanation:
First we have to look at the following formula
Vf = Vo + gt
then we work it to clear what we want
Vo + gt = Vf
gt = Vf - Vo
t = (Vf-Vo)/g
Now we have to complete the formula with the real data
Vo = 32 ft/s as the statement says
Vf = 0 because when it reaches its maximum point it will stop before starting to lower
g = -32,16 ft/s² it is a known constant, that we use it with the negative sign because it is in the opposite direction to ours
t = (0 ft/s - 32 ft/s) / -32,16 ft/s²
we solve and ...
t = 0.995 s
Now we will implement this result in the following formula to get the height at that time
h = (Vo - Vf) *t /2
h = (32 ft/s - 0 ft/s) * 0.995 s / 2
h = 32 ft/s * 0.995 s/2
h = 31.84 ft / 2
h = 15.92 ft
Answer:
The matrix is not invertible.
Step-by-step explanation:
We are given the following matrix in the question:
![A =\left[\begin{array}{ccc}-5&0&1\\-1&3&2\\0&10&6\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-5%260%261%5C%5C-1%263%262%5C%5C0%2610%266%5Cend%7Barray%7D%5Cright%5D)
Condition for invertible matrix:
A matrix is invertible if and only if the the determinant is non-zero.
We can find the determinant of the matrix as:
![|A| = -5[(3)(6)-(2)(10)]-0[(-1)(6)-(2)(0)] + 1[(-1)(10)-(3)(0)]\\|A| = -5(18-20)+(-10)\\|A| = 10-10\\|A| = 0](https://tex.z-dn.net/?f=%7CA%7C%20%3D%20-5%5B%283%29%286%29-%282%29%2810%29%5D-0%5B%28-1%29%286%29-%282%29%280%29%5D%20%2B%201%5B%28-1%29%2810%29-%283%29%280%29%5D%5C%5C%7CA%7C%20%3D%20-5%2818-20%29%2B%28-10%29%5C%5C%7CA%7C%20%3D%2010-10%5C%5C%7CA%7C%20%3D%200)
Since the determinant of the given matrix is zero, the given matrix is not invertible.
