All categories

3 years ago

Write pqqqqrr in exponential form.

Mathematics

2 answers:

Gre4nikov [31]3 years ago

6 0

Pqqqqrr in exponential form would equal to p·q^4·r^2

Dmitry [639]3 years ago

6 0

Pqqqqrr in exponential form would equal to p·q^4·r^2

You might be interested in

Your friend has 100$ when he goes to the fair and 20$ on food. Rides at the fair cost $2 per ride. Which function can be used to

andreev551 [17]

Y= 100+20-2X is the equation

4 0

4 years ago

What's 6 multiplyed by 7 add 4 and take away 3

Katyanochek1 [597]

The correct answer is 43. hope i helped:)

4 0

4 years ago

Read 2 more answers

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

4 years ago

M 1 = (2x + 28)<br> m 3= (6x + 4)<br> What is m<2<br> Enter your answer in the box.

s2008m [1.1K]

Answer:

m∠2 = 140°

Step-by-step explanation:

m∠1 = m∠3, since they're vertical angles.

Solve for x:

$2x+28=6x+4\\24=4x\\6=x$

Plug in 6 for x for either m∠1 or m∠3. Doesn't matter since they're equal.

m∠1 = (2(6) + 28)°

m∠1 = (12 + 28)°

m∠1 = 40°

Now that we know m∠1, we can now solve for m∠2.

m∠1 + m∠2 = 180°

40° + m∠2 = 180°

m∠2 = 140°

3 0

3 years ago

I really need help. answer asap and both questions plz. thank you for you help!!

lidiya [134]

Hello from MrBillDoesMath!

Answer: x = 4, slope intercept form is y = 2x + 11

Discussion:

A vertical line goes straight up and down. The only thing "fixed" about it is its x value. Hence a vertical line has an equation like "x = ?". As your line passes through (4, -3), with x value 4. its equation is x = 4.

The slope intercept form of a line is " y = mx + b" where m is the slope of the line and b is its y intercept. We are told the desired line is parallel to y = 2x -1 which means both lines have the same slope (which is 2, boldfaced, above). So, we know the slope intercept form is

y = 2x + b

but we are also told the line passes through (-3,5). Substituting these values in the above equation gives

y = 2x + b

5 = 2 (-3) + b

5 = -6 + b

b = 5 + 6 = 11

The final slope intercept form is y = 2x + 11

Regards, MrB

7 0

3 years ago