Answer:
193%
Step-by-step explanation:
40.2 - 13.7 = 26.5
26.5 ÷ 13.7 = 1.93
1.93 = 193%
Answer:
So this means the bus B covered 390-120=270 miles when bus A has already reached 390 miles.
270 miles
Step-by-step explanation:
So is A is going faster than B so A will reach the destination first.
When will A reach it's destination?
Let's find out.
To solve this problem, the following will come in handy:
Speed=distance/time or time*Speed=distance or time=distance/speed .
time=distance/speed
So it will take bus A 6 hours to cover the distance of 390 miles.
How much time would have it taken bus B to reach that same distance?
So it would have taken bus B 
hours to cover a distance of 390 miles.
So the time difference is 
hours.
It will take 
more hours than bus A for bus B to complete a distance of 390 miles.
So bus B traveled 
miles (used the time*speed=distance) after bus A got to it's destination.
So this means the bus B covered 390-120=270 miles when bus A has already reached 390 miles.
Problem 7)
The answer is choice B. Only graph 2 contains an Euler circuit.
-----------------
To have a Euler circuit, each vertex must have an even number of paths connecting to it. This does not happen with graph 1 since vertex A and vertex D have an odd number of vertices (3 each). The odd vertex count makes it impossible to travel back to the starting point, while making sure to only use each edge one time only.
With graph 2, each vertex has exactly two edges attached to it. So an Euler circuit is possible here.
================================================
Problem 8)
The answer is choice B) 5
-----------------
Work Shown:
abc base 2 = (a*2^2 + b*2^1 + c*2^0) base 10
101 base 2 = (1*2^2 + 0*2^1 + 1*2^0) base 10
101 base 2 = (1*4 + 0*2 + 1*1) base 10
101 base 2 = (4 + 0 + 1) base 10
101 base 2 = 5 base 10
C can be found using pythagoras theorem. c2=a2+b2. Now, b is not given, but we know that cos(theta)=b/c=>b=c*cos(theta). Substituting b in the above relation, c2=a2+c2(cos(theta))^2=>c2=a2/(1-cos((theta))^2). c is the squareroot of c2. Hence c=sqrt(2/(1-cos((theta))^2))
Answer: 3560
Step-by-step explanation: GCF of 400 will be 40 and the LCM will be 3600 so if you are doing LCM-GCF it would be 3560
