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2 years ago

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Suppose that f is an even function whose domain is the set of all real numbers. Then which of the following can we claim to be t

rue? The function f has an inverse f –1 that is even. The function f has an inverse f –1 that is odd. The function f has an inverse f –1, but we can't tell whether it's even or odd. f –1 is not a function. We can't tell whether or not f has an inverse.

1 answer:

miv72 [106K]2 years ago

3 0

Answer:

$f^{-1}$ is not a function.

Step-by-step explanation:

Consider the provided information.

If a function is Even function that means the graph of the function is symmetric with respect to the y-axis.

So, if (x,y) is on the graph, then (-x, y) is also on the graph.

The graph of even function is not one to one as it not satisfy the horizontal line test.

Even functions are not one-to -one, and therefore do not have inverses.

Or we can say that $f^{-1}$ is not a function.

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