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Nostrana [21]
3 years ago
10

Pemfaktoran dari 2x²+5x-18​

Mathematics
1 answer:
Harrizon [31]3 years ago
3 0

We can factor a polynomial by finding its roots. In particular, a quadratic equation has (at most) two roots x_1,\ x_2, which would allow us to write the polynomial as

p(x)=a(x-x_1)(x-x_2)

To find the solutions, we can use the quadratic formula

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} = \dfrac{-5\pm\sqrt{169}}{4} = \dfrac{-5\pm13}{4}

So, the two solutions are

\dfrac{-5+13}{4} = 2\quad\text{and}\quad\dfrac{-5-13}{4} =-\dfrac{9}{2}

And so we can factor the polynomial as follows:

2x^2+5x-18=2(x-2)\left(x+\dfrac{9}{2}\right)

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Answer:

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have a birthday in May, or they do not. The probability of a person having a birthday in May is independent of any other person. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

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Probability of a person being in May:

May has 31 days in a year of 365. So

p = \frac{31}{365} = 0.0849

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This means that n = 20

What is the probability that at the May celebration, exactly two members of the group have May birthdays?

This is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{20,2}.(0.0849)^{2}.(0.9151)^{18} = 0.2773

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

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