Find the lowest natural number which when divided by 12, 45, 15 and 10 leaves the remainder of

Mathematics

1 answer:

Levart [38]3 years ago

5 0

12=2*2*3
45=3*3*5
15=3*5
10=2*5
L.C.M=2*2*3*3*5=180
required number 180+2=182

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