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s2008m [1.1K]
3 years ago
14

What is the perimeter of the shape below if each unit is 1 foot

Mathematics
2 answers:
icang [17]3 years ago
6 0
Well, we need the picture / the shape...
NikAS [45]3 years ago
5 0
It depends on the shape.
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Write the absolute value inequality in the form x−b ≤c or x−b ≥c that has the solution set −1≤x≤3.
stealth61 [152]

Answer:

|x - 1| ≤ 2

Step-by-step explanation:

b = (-1+3)/2 = 1

c = 3-1 = 2

|x - 1| ≤ 2

4 0
3 years ago
What's the lowest point of the graph of 10y + 30 = x?
inna [77]
The lowest must be ,,,,,when x=0
so
10y+30=0
10y=-30
y=-3
So your answer is (0, -3)
3 0
4 years ago
Please help me with this sum​
sergey [27]

its upsidedown what are you doing

3 0
3 years ago
There are three different hoses used to fill a pool: hose x, hose y, and hose z. Hose x can fill the pool in a days, hose y in b
WARRIOR [948]

Answer:

C) I and III only

Step-by-step explanation:

Let full pool is denoted by O

Days Hose x takes to fill pool O = a

Pool filled in one day x = O/a

Days Hose y takes to fill pool O = b

Pool filled in one day y = O/b

Days Hose z takes to fill pool O = c

Pool filled in one day z = O/c

It is given that

                         a>b>c

a>b>c>d\\\implies x

Days if if x+y+z fill the pool together = d

1 day if x+y+z fill the pool together =O(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})=\frac{O}{d}---(1)

I) d < c

d are days when hose x, y, z are used together where as c are days when only z is used so number of days when three hoses are used together must be less than c when only z hose is used. So d < c

III) \frac{c}{3}

Using (1)

\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad(a>b>c)\\(ab+bc+ca)\frac{abc}{3ab}\\\\d>\frac{c}{3}

Similarly

\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad a>b>c\\(ab+bc+ca)>3bc\\\\d=\frac{abc}{ab+bc+ca}

So,

\frac{c}{3}

3 0
3 years ago
Simplify. Question is in the picture.
sasho [114]

\tt 3\sqrt{6}-10 \sqrt{2}\cdot \sqrt{3} =3\sqrt{6}-10 \sqrt{6}=\boxed{\tt -7\sqrt{6}}

5 0
3 years ago
Read 2 more answers
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