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kotegsom [21]
3 years ago
12

(-19, -13), (11, -3)

Mathematics
1 answer:
Mashutka [201]3 years ago
8 0

Answer:

Your answer is -256

Step-by-step explanation:

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Sin(cos^-1 x)<br><br> how to solve?
tatiyna

Answer:

sin(cos^{-1}x)=\sqrt{1-x^2}

Step-by-step explanation:

let us assume

cos^{-1} x=\theta\\x=cos\theta\\

now

sin(cos^{-1}x) can be written as sin\theta

we know  sin^2\theta+cos^2\theta=1

so sin^2\theta=1-cos^2\theta

sin\theta=\sqrt{1-cos^2\theta}

now from above equation we can say that

sin\theta=\sqrt{1-x^2}

sin(cos^{-1}x)=\sqrt{1-x^2}

7 0
3 years ago
3x - 2 + x + 8 = -(9x + 7
dalvyx [7]

Answer:

no

Step-by-step explanation:

3x−2+x+8=−9x−7

4x+6=−9x−7

4x+6+9x=−7

13x+6=−7

13x=−13

x=−1

5 0
2 years ago
What is 71234567890-1234567890
luda_lava [24]
The answer is 70 billion
8 0
4 years ago
Read 2 more answers
1 Ms. Omar runs the school tennis club. She has a bin of tennis balls and rackets.
fenix001 [56]

Answer:

Step-by-step explanation:

          3             6             9             12          15

5        .

10                     .

15                                        .

20                                                   .

25                                                                          .

6 0
3 years ago
A certain quadratic function has x-intercepts at 2 and 3. What are the x-coordinates of its vertex?
Alik [6]
<h3>Answer:  D) 5/2</h3>

==================================================

Explanation:

The parabola is symmetric around its vertex. This means that the roots are the same horizontal distance away from the vertex. Furthermore, we can apply the midpoint formula on the given roots to find the x coordinate of the vertex.

Find the midpoint of 2 and 3 to get (2+3)/2 = 5/2

Note: 5/2 = 2.5

6 0
3 years ago
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