Answer:
Answer b of the first one
answer of q9
Step-by-step explanation:
(x+iy)(2−3i)=4+i
2x−(3x)i+(2y)i−3yi
2
=4+i
Real
2x+3y
+
Imaginary
(2y−3x)
i=4+i
Comparing the real & imaginary parts,
2x+3y=4--------------------------(1)
2y−3x=1----------------------------(2)
Solving eq(1) & eq(2),
4x+6y=8
−9x+6y=3
13x=5⇒x=
13
5
y=
13
14
∴(x,y)=(
13
5
,
13
14
)
Was this answer helpful?
upvote
196
downvote
23
SIMILAR QUESTIONS
star-struck
If e
x+iy
=α+iβ, then x+iy is called logarithm of α+iβ to the base e.∴log
e
(x+iy)=log
e
(re
iθ
) =log
e
r+iθ where r is modulus value of x+iy & θ be the argument of x+iy If i
α+iβ)
=α+iβ, then α
2
+β
2
equals
Hard
View solution
>
The modulus of (1 + i) (1 + 2i) (1 + 3i) is equal to
Answer:
Step-by-step explanation:
y intercept is when x = 0
So, Putting x = 0 in the above function
=> f(0) =
=> f(0) = 2*1
=> f(0) = 2
So, y-intercept is (0,2)
9514 1404 393
Answer:
1/4
Step-by-step explanation:
The common ratio is the ratio of successive terms:
16/64 = 4/16 = 1/4
The common ratio is 1/4.
The cube root is 10 bc 10x10x10 = 100