30 pts. In one study, it was found that the correlation coefficient between two variables is -0.95

Mathematics

2 answers:

nikitadnepr [17]3 years ago

8 0

Answer:

B. There is a strong negative association between the variables.

Step-by-step explanation:

The more negative the correlation coefficient, the more negative the association. The more positive the correlation coefficient, the more positive the association. If the correlation coefficient is near zero, there is no correlation.

ch4aika [34]3 years ago

3 0

Answer:

The correct option is B.

Step-by-step explanation:

It is given that the correlation coefficient between two variables is -0.95.

Correlation coefficient between two variables is denotes by ρ. The value of ρ is leis between -1 to 1.

If $\rho=-1$ , then it represent perfect negative correlation.

If $\rho=1$ , then it represent perfect positive correlation.

If $\rho=0$ , then it represent no relationship between the variables.

Since the -0.95 is near to the value -1, therefore we can say that there is a strong negative association between the variables. Option B is correct.

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14. 1.5, 10 <- Answer
15. 5,1 <- Answer

Proof 14

Solve the following system:
{2 x - y = -7 | (equation 1)
4 x - y = -4 | (equation 2)
Swap equation 1 with equation 2:
{4 x - y = -4 | (equation 1)
2 x - y = -7 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x - y = -4 | (equation 1)
0 x - y/2 = -5 | (equation 2)
Multiply equation 2 by -2:
{4 x - y = -4 | (equation 1)
0 x+y = 10 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = 6 | (equation 1)
0 x+y = 10 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 3/2 | (equation 1)
0 x+y = 10 | (equation 2)
Collect results:
Answer: {x = 1.5
y = 10

Proof 15.

Solve the following system:
{5 x + 7 y = 32 | (equation 1)
8 x + 6 y = 46 | (equation 2)
Swap equation 1 with equation 2:
{8 x + 6 y = 46 | (equation 1)
5 x + 7 y = 32 | (equation 2)
Subtract 5/8 × (equation 1) from equation 2:{8 x + 6 y = 46 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Divide equation 1 by 2:
{4 x + 3 y = 23 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Multiply equation 2 by 4/13:
{4 x + 3 y = 23 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 20 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 5 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer: {x = 5 y = 1

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