Ask question

Ask question

All categories

3 years ago

14

In a certain city, the street blocks have a uniform size of 90 meters north-south by 260 meters east-west. If a typical neighbor

hood has two blocks east-west by three works north-south, how much area does it cover?

1 answer:

Mumz [18]3 years ago

3 0

70,200 to multiply 90x3x260=70,200

You might be interested in

Find the 95% confidence interval for estimating the population mean μ

AVprozaik [17]

We first need to determine whether we are dealing with means or proportions in this problem. Since we are given the sample and population mean, we know that we are dealing with means.

Since we have one sample mean, this means we are creating a confidence interval for one sample (1 Samp T Int).

Normally we would check for conditions, but since this is not formulated as a "real-world scenario" type problem, it is hard to check for randomness and independence. Therefore, I will be excluding conditions from this answer.

<h3>Confidence Interval Formula</h3>

The formula for constructing a <u>confidence interval for means</u> is as follows:

$\displaystyle \overline{x} \pm t^*\big{(}\frac{\sigma}{\sqrt{n} } \big{)}$

We are given these variables:

$\overline{x}=50$
$n=60$
$\sigma=10$

Plug these values into the formula for the confidence interval:

$\displaystyle 50\pm t^* \big{(}\frac{10}{\sqrt{60} } \big{)}$

<h3>Finding the Critical Value (t*)</h3>

In order to find t*, we can use this formula:

$\displaystyle \frac{1-C}{2}=A$

Calculating the z-score associated with "A" will give us t*.

So, let's plug in the confidence interval 95% (.95) into the formula:

$\displaystyle \frac{1-.95}{2}=.025$

Use your calculator or a t-table to find the z-score associated with this area under the curve.. you should get:

$t^*=1.96$

<h3>Constructing Confidence Interval</h3>

Now, let's finish the confidence interval we created:

$\displaystyle 50\pm 1.96 \big{(}\frac{10}{\sqrt{60} } \big{)}$

We can calculate the confidence interval, using this formula, to be:

$\boxed{(47.4697, \ 52.5303)}$

<h3>Interpreting the Confidence Interval</h3>

We are 95% confident that the true population mean μ lies between <u>47.4697 and 52.5303</u>.

8 0

1 year ago

2x+4x+6x=10x+84 please help solve

Natasha2012 [34]

2x+4x+6x = 10x+84

12x-10x = 84

2x = 84

x = 42

3 0

3 years ago

Read 2 more answers

Find an equation of variation in which y varies jointly as x and z and inversely as the product of w and p, where yequalsstartf

leva [86]

To solve this problem you must apply the proccedure shown below:

1. You have that $y$ varies jointly as $x$ and $z$ and inversely as the product of $w$ and $p$ . Therefore, you can write the following equation, where $k$ is the constant of proportionality:

$y=k(\frac{xz}{wp} )$

2. Now, you must solve for the constant of proportionality, as following:

$k=\frac{ywp}{xz}$

3. Susbtiute values:

$y=\frac{7}{28} \\ x=7\\ z=4\\ w=7\\ p=8$

$k=\frac{(\frac{7}{28})(7)(8))}{(7)(4)} =0.5$

4. Substitute the value of the constant of proportionality into the equation:

$y=0.5(\frac{xz}{wp})$

The answer is: $y=0.5(\frac{xz}{wp})$

7 0

3 years ago

Help math maths math math

Travka [436]

Answer:

Step-by-step explanation:

remeber is (x,y) so it will be like this $\frac{6-3}{4-6} =-\frac{3}{2}$

5 0

2 years ago

An item is regularly priced at 85$. It is on sale for 80% off the regular price. How much is discounted from the regular price?

laila [671]

$68 is discounted from the regular price.

To find this, you first divide 80% by 100 to get 0.8 (the decimal form of the percentage). Then, simply multiply 0.8 by 85 (or vise verse) to get $68. Since the question is asking for how much is discounted from the regular price, the final answer would be $68.

I hope this helps!

4 0

2 years ago