Use photo math it will help
Answer:
these three apply:
ΔCBA ≈ ΔFED
ΔBAC ≈ ΔEDF
ΔABC ≈ ΔDEF
Step-by-step explanation:
A. 2x^2 - 3x + 10 = 2x + 21
2x^2 - 3x - 2x + 10 - 21 = 0
2x^2 - 5x - 11 = 0 (quadratic equation)
2x^2 - 6x - 7 = 2x^2
2x^2 - 2x^2 - 6x - 7 = 0
-6x - 7 = 0 (not a quadratic equation)
5x^2 + 2x - 4 = 2x^2
5x^2 - 2x^2 + 2x - 4 = 0
3x^2 + 2x - 4 (quadratic equation)
5x^3 - 3x + 10 = 2x^2
5x^3 - 2x^2 - 3x + 10 = 0 (not a quadratic equation)
Therefore, options a and c can be solved using the quadratic formula.
Answer:
305
Step-by-step explanation:
23×9+98
207+98
305
Answer:
-(1/3)x+1>y
2x-3≥y
If x<12/7 then 2x-3≥y
and if x≥12/7 then -(1/3)x+1>y