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3 years ago

Add the polynomials (2x + 3) + (2x + 1)

Mathematics

2 answers:

anyanavicka [17]3 years ago

6 0

Answer:

4(x+1)

Step-by-step explanation:

Factor 2x+3+2x+1

4x+4

=4(x+1)

hodyreva [135]3 years ago

6 0

Answer:

here's your answer

please mark me as brainliest

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The minimum number of games Enzo could have played is 5

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The marketing director of a large department store wants to estimate the average number of customers who enter the store every f

Dahasolnce [82]

Answer:

$36.5674\leq x'\leq61.4326$

Step-by-step explanation:

If we assume that the number of arrivals is normally distributed and we don't know the population standard deviation, we can calculated a 95% confidence interval to estimate the mean value as:

$x-t_{\alpha /2}\frac{s}{\sqrt{n} } \leq x'\leq x-t_{\alpha /2}\frac{s}{\sqrt{n} }$

where x' is the population mean value, x is the sample mean value, s is the sample standard deviation, n is the size of the sample, $\alpha$ is equal to 0.05 (it is calculated as: 1 - 0.95) and $t_{\alpha /2}$ is the t value with n-1 degrees of freedom that let a probability of $\alpha/2$ on the right tail.

So, replacing the mean of the sample by 49, the standard deviation of the sample by 17.38, n by 10 and $t_{\alpha /2}$ by 2.2621 we get:

$49-2.2621\frac{17.38}{\sqrt{10} } \leq x'\leq 49+2.2621\frac{17.38}{\sqrt{10} }\\49-12.4326\leq x'\leq 49+12.4326\\36.5674\leq x'\leq61.4326$

Finally, the interval values that she get is:

$36.5674\leq x'\leq61.4326$

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3 years ago

Given A and B are vertical angles with m∠A = 20x + 10 and m∠B = 30x – 10. What is x? 3.6 4 2 9

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Answer:

Step-by-step explanation:

∠A and ∠B are vertical => ∠A=∠B

20x+10=30x-10

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-10x= -20

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Good luck!

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3 years ago

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Can someone help 2d + 1/5 = 3/5

bearhunter [10]

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3 years ago

Reflect the given triangle over the x axis. <br> [3 6 3<br> -3 3 3]

ivolga24 [154]

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Answer:

[[3, 6, 3] [3, -3, -3]]

Step-by-step explanation:

Reflecting over the x-axis changes the sign of the y-coordinate. The reflected coordinates are ...

$\left[\begin{array}{ccc}3&6&3\\3&-3&-3\end{array}\right]$

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