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3 years ago

Can someone help 2d + 1/5 = 3/5

1 answer:

8 0

$2d+\dfrac{1}{5}=\dfrac{3}{5}\ \ \ \ \ |subtract\ \dfrac{1}{5}\ from\ both\ sides\\\\2d=\dfrac{2}{5}\ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{d=\frac{1}{5}}$

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The amount of $180.00 is what percent greater than $135.00

olga nikolaevna [1]

Percent change = ((new value) - (old value))/(old value) × 100%
= (180 -135)/135 × 100%
= 33 1/3%

180 is about 33% greater than 135.

8 0

3 years ago

Use what you already know to find a, b, and c.

Valentin [98]

Answer:

Use the "find vertically opposite angle" method.

a = 80°

To find the other angles:

Since the angles equal up to 360 which makes a full circle shape...

360 - 80 - 80 = 200 (B and C)

200 ÷ 2 = 100 (Angle for B and C since they are vertically opposite, hence having the same angle)

b = 100°

c = 100°

8 0

3 years ago

HELP PLZZZZZZZZ HELP PLZZZZZZZZZ

Lesechka [4]

1. 6.73 x 10^6
2. 1.33 x 10^4
3.9.77 x 10^22
4. 3.84 x 10^5
The rest i didn’t understand what where you trying to say

7 0

3 years ago

The table displays the number of students in each grade at Richmond High School who will or will not be attending the amusement

Pani-rosa [81]

Answer:

$P( eleventh\: \: |\: \: FT)= 0.2453 \\\\P( eleventh\: \: |\: \: FT)= 24.53\% \\\\$

Step-by-step explanation:

We are given a joint probability table.

There are four different graders in a school

1. Grade Ninth

2. Grade Tenth

3. Grade Eleventh

4. Grade Twelfth

Field trip refers to the students who will attending the amusement park field trip.

No field trip refers to the students who will not be attending the amusement park field trip.

We want to find out the probability that the selected student is an eleventh grader given that the student is going on a field trip.

$P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)}$

Where P(eleventh and FT) is the probability of students who are in eleventh grade and will be going to field trip

$P(eleventh\: and \: FT) = \frac{13}{92} \\\\P(eleventh \: and \: FT) = 0.1413$

Where P(FT) is the probability of students who will be going to field trip

$P(FT) = \frac{12}{92} + \frac{9}{92} + \frac{13}{92} + \frac{19}{92}\\\\P(FT) = 0.1304 + 0.0978 + 0.1413 + 0.2065\\\\P(FT) = 0.576 \\\\$

So the required probability is

$P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)} \\\\P( eleventh\: \: |\: \: FT)= \frac{0.1413}{0.576} \\\\P( eleventh\: \: |\: \: FT)= 0.2453 \\\\P( eleventh\: \: |\: \: FT)= 24.53\% \\\\$

6 0

3 years ago

A rare book was purchased for $200 and then it was sold for $400. What percent increase was that

hram777 [196]

Answer:

100% increase

Step-by-step explanation:

8 0

2 years ago