Question

Write an equation of the line that passes through (-5, -2) and is parallel to y=2/3x+1 y=?

Answer 1

Answer:

         y = ²/₃x + ⁴/₃

Step-by-step explanation:

The point-slope form of the equation of line: y - y₁ = m(x - x₁), where m is the slope and (x₁, y₁) is the point the line passing through.

y=m₁x+b₁   ║   y=m₂x+b₂   ⇔    m₁ = m₂

{Two lines are parallel if  their slopes are equal}

y = 2/3x + 1   ⇒    m₁ = 2/3    ⇒    m₂ = 2/3

(-5, -2)    ⇒    x₁ = -5,  y₁ = -2

point-slope form:

y - (-2) = 2/3(x - (-5))

y + 2 = 2/3(x + 5)

y + 2 = 2/3x + 10/3               {subtact 2 from both sides}

y = 2/3x + 4/3         ←   slope-intercept form

Answer 2

Answer:

        y = ²/₃x + ⁴/₃

Step-by-step explanation:

The point-slope form of the equation of line: y - y₁ = m(x - x₁), where m is the slope and (x₁, y₁) is the point the line passing through.

y=m₁x+b₁   ║   y=m₂x+b₂   ⇔    m₁ = m₂

{Two lines are parallel if  their slopes are equal}

y = 2/3x + 1   ⇒    m₁ = 2/3    ⇒    m₂ = 2/3

(-5, -2)    ⇒    x₁ = -5,  y₁ = -2

point-slope form:

y - (-2) = 2/3(x - (-5))

y + 2 = 2/3(x + 5)

y + 2 = 2/3x + 10/3               {subtact 2 from both sides}

y = 2/3x + 4/3         ←   slope-intercept form