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velikii [3]
4 years ago
14

Is the relation {(1, 3), (–4, 0), (3, 1), (0, 4), (2, 3)} a function? Why or why not? No, the range value 3 corresponds to two d

omain values, 1 and 2. Yes, there is no value in the domain that corresponds to more than one value of the range. Yes, the range value 3 corresponds to two domain values, 1 and 2. No, there is no value in the domain that corresponds to more than one value of the range.
Mathematics
2 answers:
Lynna [10]4 years ago
4 0

Answer:

Yes, there is no value in the domain that corresponds to ore than one value of the range. Hope I helped


yaroslaw [1]4 years ago
3 0

Answer:  The correct option is

(2). Yes, there is no value in the domain that corresponds to more than one value of the range.

Step-by-step explanation:  We are given to check whether the following relation is a function or not.

R=\{(1, 3), (-4, 0), (3, 1), (0, 4), (2, 3)\}.

We know that,

the first element of each ordered pair in the relation above makes the domain and the second element of each ordered pair makes the range.

So, the domain will be  D=\{1,-4,3,0,2\},

and the range will be  R=\{3,0,1,4,3\}.

A RELATION will be a function if each value in the domain correspond to one and only one value in the range.

Since, in the set R, there is no value in the domain that corresponds to more than one value of the range, so

The given relation 'R' is a FUNCTION.

Thus, the correct option is

(2). Yes, there is no value in the domain that corresponds to more than one value of the range.

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This is the two that go together, but are separate questions
ira [324]

Answers:

Option 1)

6a + 8s = 102

14a + 4s = 150

each adult ticket costs 9 dollars

===================================================

Explanation:

6 adult tickets and 8 student tickets bring in $102, so that means 6a+8s = 102

14 adult tickets and 4 students tickets bring in $150, so 14a+4s = 150

The system of equations is

\begin{cases}6a+8s = 102\\14a+4s = 150\end{cases}

If we multiply both sides of the second equation by -2, we get this updated system

\begin{cases}6a+8s = 102\\-28a-8s = -300\end{cases}

Add the equations straight down

6a+(-28a) = -22a

8s+(-8s) = 0s = 0 ... the 's' terms go away

102+(-300) = -198

So we end up with the equation -22a = -198 and that solves to a = 9 after dividing both sides by -22.

Each adult ticket costs $9

If you want the value of s, then

6a+8s = 102

6(9)+8s = 102

54 + 8s = 102

8s = 102-54

8s = 48

s = 48/8

s = 6

Meaning each student ticket costs $6

Or you could use the other equation

14a+4s = 150

14(9)+4s = 150

126+4s = 150

4s = 150-126

4s = 24

s = 24/4

s = 6

We get the same value of s

5 0
3 years ago
Find the value of x in the parallelogram below​
aleksley [76]

68° + x = 180°;

x = 180° - 68° = 112°.

Answer: 112°.

8 0
3 years ago
The amount y (in grams) of the radioactive isotope fermium-253 remaining after t hours is y=a(0.5)t/72, where a is the initial a
almond37 [142]

Answer:

Per hour decay of the isotope is 0.96%.

Step-by-step explanation:

Amount of radioactive element remaining after t hours is represented by

y=a(0.5)^{\frac{t}{72}}

where a = initial amount

t = duration of decay (in hours)

Amount remaining after 1 hour will be,

y=a(0.5)^{\frac{1}{72} }

y = 0.9904a

So amount of decay in one hour = a - 0.9904a

                                                      = 0.0096a gms

Percentage decay every hour = \frac{\text{Amount of decay}}{\text{Initial amount}}\times 100

                                                  = \frac{0.0096a}{a}\times 100

                                                  = 0.958 %

                                                  ≈ 0.96 %

Therefore, per hour decay of the radioactive isotope is 0.96%.

7 0
4 years ago
Solve the equation for x by graphing.-4x-1 5x=4
Gemiola [76]

Answer: Undefined

Step-by-step explanation:

slope is undefined

no y intercept

This line is vertical

4 0
4 years ago
10
Anni [7]

Answer:

first one. Since its X crosses or passes (2,0)

Step-by-step explanation:

5 0
3 years ago
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