Answer:
<u>39.5 miles/gallon.</u>
Step-by-step explanation:
6 gallons of gas used to drive 237 miles
The rate of her car uses gas in miles per gallon =
![\frac{237 miles}{6 gallons} = \frac{237}{6} = 39.5 \ miles/gallons](https://tex.z-dn.net/?f=%5Cfrac%7B237%20miles%7D%7B6%20gallons%7D%20%3D%20%5Cfrac%7B237%7D%7B6%7D%20%3D%2039.5%20%5C%20miles%2Fgallons)
Which mean the car will consume 1 gallon for each 39.5 miles.
Answer:
![\frac{63}{15 - c} - \frac{63}{15 + c} = 4](https://tex.z-dn.net/?f=%5Cfrac%7B63%7D%7B15%20%20-%20c%7D%20-%20%5Cfrac%7B63%7D%7B15%20%20%2B%20c%7D%20%3D%204)
Step-by-step explanation:
The systems of equations are
Let us assume the rate of the current be c
Now actual speed against the current is (15 - c)
And, the actual speed with the current is (15 + c)
Here we applied the time formula i.e. distance by speed
Also the upstream time - downstream time = 4
Now the equations are
![\frac{63}{15 - c} - \frac{63}{15 + c} = 4](https://tex.z-dn.net/?f=%5Cfrac%7B63%7D%7B15%20%20-%20c%7D%20-%20%5Cfrac%7B63%7D%7B15%20%20%2B%20c%7D%20%3D%204)
It should be 3366. To find the percent increased, multiply 3300 by .02 and add that to 3300, giving you 3366.
Answer:
∠ABC= 45°
Step-by-step explanation:
∠ABC= ∠BCD (alt. ∠s, AB//CD)
(2x +15)°= (3x)°
2x +15= 3x
3x-2x= 15 <em>(</em><em>-2x </em><em>on </em><em>both </em><em>sides)</em>
x= 15
Substituting the value of x:
∠ABC
= ∠BCD
= [3(15)]°
= 45°