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34kurt
3 years ago
15

The average of your first 6 tests is 82. If your test average after your seventh test is an 80.5, what did you score on the seve

nth test?
Question 2 options:
Mathematics
1 answer:
mart [117]3 years ago
7 0
So average is  of the first 6 tests is 82   well that means 

(test1 + test2+ test3+ test4 + test5+test6)/6 = 82

so now let do some cross multiplliying 

test1 + test2 + test3 + test 4 + test5 +test6 = 82*6

test1 + test2 + test3 + test 4 + test5 +test6  = 492

now lets see if we can find that 7th test score

(test1 + test2 + test3 + test4 + test5 +test6 + test7)/7 = 80.5

So look we found test1 + test2 + test3 + test4 + test5 +test6 to be 492 so lets substitute. 

(492 + test7 )/7 = 80.5

test7 = (80.5*7)-492 = 71.5 



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Find the area of a rhombus with side length 6 and an interior angle with measure $120^\circ$.
Serhud [2]

Answer:

The area of a rhombus is 18\sqrt{3} square units.

Step-by-step explanation:

Side length of rhombus = 6 units.

Interior angle of rhombus = 120°

another Interior angle of rhombus = 180°-120° = 60°.

Draw an altitude.

In a right angled triangle

\sin \theta=\frac{opposite}{hypotenuse}

\sin (60)=\frac{h}{6}

\frac{\sqrt{3}}{2}=\frac{h}{6}

Multiply both sides by 6.

3\sqrt{3}=h

The height of the rhombus is 3\sqrt{3}.

Area of a rhombus is

Area=base\times height

Area=6\times 3\sqrt{3}

Area=18\sqrt{3}

Therefore, the area of a rhombus is 18\sqrt{3} square units.

8 0
3 years ago
Read 2 more answers
Factor each completely. <br><br>10a² - 9a + 2 <br><br>​
Sophie [7]

Answer:

a= \frac{2}{5} or \frac{1}{2}

Step-by-step explanation:

Equate the equation to zero

10a^{2}-9a+2=0

10a^{2}-5a-4a+2=0

5a(2a-1)-2(2a-1)=0

Write out the factors

(5a-2)(2a-1)=0

Then equate each factor to zero

5a-2=0 OR 2a-1=0

5a=2  OR  2a=1

a= \frac{2}{5}   OR a= \frac{1}{2}

a=\frac{2}{5} or \frac{1}{2}

3 0
3 years ago
Solve for x and y<br> 6(ax + by) = 3a + 2b ; 6(bx-ay) = 3b - 2a
slava [35]

6×ax+6×by =6ax+6by =3a+2b,6×bx-6×ay=3b-2a=6bx-3a+2b

4 0
3 years ago
How does the volume of a cylinder change if the radius is quadrupled and the height is reduced to a third of its original size?
vredina [299]
Oh yay, proportional thinking! (Vicious sarcasm). Alright, let's do this:

<span>Volume of the cylinder = </span><span>π(h)r^2
New volume = </span><span>π(h/3)(4r)^2
= (1/3)</span><span>π(h)(16r^2)
=16*(1/3)</span><span>π(h)r^2
=(16/3)</span><span>π(h)r^2

Therefore, it's D. Though it's spelled pi, and you should really use the ^ symbol. </span>
8 0
3 years ago
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An isosceles triangle with congruent sides of 16.2 cm and a third side half that length
Zielflug [23.3K]

Answer: option iii

The perimeter of an isosceles triangle with congruent sides of 16.2 cm and a third side half that length is 16.2+16.2+8.1 = 40.5 cm

Explanation:

The perimeter of an isosceles triangle with congruent sides of 16.2 cm and a third side half that length is 16.2+16.2+8.1 = 40.5 cm

First side is = 16.2 cm

Second side is = 16.2 cm

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The perimeter of an isosceles triangle with congruent sides of 16.2 cm and a third side half that length is 16.2+16.2+8.1 = 40.5 cm

7 0
3 years ago
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