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faust18 [17]
4 years ago
15

You drive 200 miles in 3 hours before stopping for lunch and gas. After lunch you

Physics
1 answer:
Paraphin [41]4 years ago
4 0

Given :

You drive 200 miles in 3 hours before stopping for lunch and gas. After lunch you  travel 250 miles in an hour and a half.

To Find :

Average speed.

Solution :

We know, average speed is given by :

v=\dfrac{\text{Total distance covered}}{\text{Total time taken}}\\\\v=\dfrac{200+250}{3+1.5}\ miles/hr\\\\v=\dfrac{450}{4.5}\ miles/hr\\\\v=100\ miles/hr

Therefore, average speed of the journey is 100 miles/hr.

Hence, this is the required solution.

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The diagram shows the electric field lines surrounding two positive point charges. If the charge on the right were replaced with
WINSTONCH [101]

Answer:

Explanation:

The wording on some of these choices is very strange; I'm not sure exactly what they are stating. First of all, A. is definitely a choice because if both the charges were opposite, they would be attracted to one another as opposed to be repelled away from one another, as they are when they are both positive. What happens is that the charges go OUT from the positive charge and INTO the negative; so as far as the field lines around both charges would change direction...no; only the direction of the field lines would change on the positive charge (which is the one on the left). In that space where D is filled in by the field lines going OUT of the positive charge and INTO the negative one, the lines there are naturally closer together, and that is the point where the charge is the greatest. So if that is what is meant by the field lines getting closer together, then yes, they do. As far as choice D. again the field lines on the negative charge don't change, only the ones on the positive charge change.

4 0
3 years ago
A hydraulic press has a safety feature which consists of a hydraulic cylinder with a piston at one end and a safety valve at the
Sergio039 [100]

Answer:

Explanation:

radius of cylinder r₁ = .02 m

radius of safety valve r₂ = .0075 m

force exerted by spring on safety valve = 950 x .0085 = 8.075 N .

Force required on piston of cylinder = F

Applying Pascal's law

8.075 / 3.14 x .0075²  =  F / 3.14 x .02²

F = 8.075 x .02² / .0075²

= 8.075 x 7.111

= 57.42 N .

6 0
3 years ago
A bomb of mass 6kg initially at rest explodes into two fragments of masses 4kg and2kg respectively. If the greater mass moves wi
uysha [10]

Answer:

v = 10 [m/s].

Explanation:

The largest mass is that of 4 [kg], in this way the momentum can be calculated by means of the product of the mass by velocity.

P=m*v\\

where:

P = momentum [kg*m/s]

m = mass = 4 [kg]

v = velocity = 5 [m/s]

Now the momentum:

P=4*5\\P=20[kg*m/s]

This same momentum is equal for the other mass, in this way we can find the velocity.

P=m*v\\20=2*v\\v=10[m/s]

4 0
3 years ago
A 780g, 50-cm-long metal rod is free to rotate about a frictionless axle at one end. While at rest, the rod is given a short but
Semmy [17]

Answer:

9.6 rad/s

Explanation:

L = length of the metal rod = 50 cm = 0.50 m

M = Mass of the long metal rod = 780 g = 0.780 kg

Moment of inertia of the rod about one end is given as

I = \frac{ML^{2}}{3} = \frac{(0.780)(0.50)^{2}}{3} = 0.065 kgm^{2}

F = force applied by the hammer blow = 1000 N

Torque produced due to the hammer blow is given as

\tau = \frac{FL}{2}

\tau = \frac{(1000)(0.50)}{2}

\tau = 250 Nm

t = time of blow = 2.5 ms = 0.0025 s

w = Angular velocity after the blow

Using Impulse-change in angular momentum, we have

I w = \tau t\\(0.065) w = (250) (0.0025)\\w = 9.6 rads^{-1}

5 0
3 years ago
A 48.5 kg student runs down the sidewalk and jumps with a horizontal speed of 4.25 m/s onto a stationary skateboard. The student
storchak [24]

<u>Answer:</u>

2.39 kg

<u>Explanation:</u>

There is conservation of momentum here in this problem so we will use the following problem:

m_1u_1+m_2u_2=(m_1+m_2)v

where the mass of the student m_1 is 48.5 kg,

the mass of the skateboard m_2 is m_2 kg,

the initial speed of the student u_1 is 4.25 m/s; and

the speed of the student and skateboard  v is 4.05 m/s.

So substituting the given values in the above formula to get:

(48.5*4.25) + (m_2 * 0) = (48.5 + m_2 ) * 4.05

206.125=196.425+4.05m_2

206.125 - 196.425 = 4.05m_2

m_2=\frac{9.7}{4.05}

m_2=2.39

Therefore, the mass of the skateboard is 2.39 kg.

7 0
3 years ago
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