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astraxan [27]
3 years ago
10

A 780g, 50-cm-long metal rod is free to rotate about a frictionless axle at one end. While at rest, the rod is given a short but

sharp 1000N hammer blow at the CENTER of the rod, aimed in a direction that causes the rod to rotate on the axle. The blow lasts a mere 2.5ms.
What is the rod's angular velocity immediately after the blow? The book gives the answer 8.0rad/s
Physics
1 answer:
Semmy [17]3 years ago
5 0

Answer:

9.6 rad/s

Explanation:

L = length of the metal rod = 50 cm = 0.50 m

M = Mass of the long metal rod = 780 g = 0.780 kg

Moment of inertia of the rod about one end is given as

I = \frac{ML^{2}}{3} = \frac{(0.780)(0.50)^{2}}{3} = 0.065 kgm^{2}

F = force applied by the hammer blow = 1000 N

Torque produced due to the hammer blow is given as

\tau = \frac{FL}{2}

\tau = \frac{(1000)(0.50)}{2}

\tau = 250 Nm

t = time of blow = 2.5 ms = 0.0025 s

w = Angular velocity after the blow

Using Impulse-change in angular momentum, we have

I w = \tau t\\(0.065) w = (250) (0.0025)\\w = 9.6 rads^{-1}

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Why is carbon said to provide a “backbone” in many molecules?(1 point)
slega [8]

Answer:

The carbon atom has unique properties that allow it to form covalent bonds to as many as four different atoms, making this versatile element ideal to serve as the basic structural component, or “backbone,” of the macromolecules.

3 0
3 years ago
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed
gregori [183]

Answer:

the rate of the change of the length of the shadow is - 0.8625 m/s.

The negative(-) sign means the length of the shadow decreases at a rate of 0.8625 m/s.

Explanation:

Given the data in the question;

Let x represent the man's distance from building,

initially x = 1m2

dx/d t= -2.3 m/s

Also Let y represent shadow height

so we determine dy/dt when x is 4m from the building

form the image description of the problem, we see two-like triangles with the same base and height ratios

so

 2 / (12-x) = y / 12

24 = y(12 - x )

y = 24 / (12-x)

dy/dt = 24/(12-x)² × dx/dt

Now at x = 4,

we substitute

dy/dt will be;

⇒ 24/(12 - 4)² × -2.3

= 24/64 - 2.3

= 0.375 × -2.3

dy/dt = - 0.8625 m/s

Therefore, the rate of the change of the length of the shadow is - 0.8625 m/s.

The negative(-) sign means the length of the shadow decreases at a rate of 0.8625 m/s.

5 0
3 years ago
A person is attracted toward the centerof the earth by a 500 n gravitational force. the force with which the earth is attracted
nignag [31]
500 N  is the answer, you just tell that the moon is attracted towards the person because of the Earth's huge mass. 
4 0
3 years ago
SOMEONE PLSSSS HELP ME WITH THIS QUESTION!!
Hitman42 [59]
The answer is indeed B
4 0
3 years ago
Orlat
Nana76 [90]

The maximum force that the athlete exerts on the bag is equal to 1,500 N and in the opposite direction as the force that the bag exerts on the athlete.

<h3>Newton's third law of motion</h3>

Newton's third law of motion states that action and reaction are equal and opposite.

Fa = -Fb

The force exerted by the athlete on the bag is equal to the force the bag exerted on the athlete but in opposite direction.

Thus, the maximum force that the athlete exerts on the bag is equal to 1,500 newtons and in the opposite direction as the force that the bag exerts on the athlete.

Learn more about force here: brainly.com/question/12970081

#SPJ1

8 0
2 years ago
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