Answer:
1/8
Explanation:
Given that the trihybrid parents have AaBbCc genotype for fruit color. The trait is a quantitative trait i.e. each dominant allele will have an additive effect on it. In this case, AaBbCc and AABBCC will not produce same fruit color because AaBbCc has only three loci contributing to the color while in AABBCC all the six loci are contributing to the color. For an offspring to be exactly similar to the AaBbCc parents it should have the same genotype of AaBbCc.
The probability of Aa to come from a cross between Aa and Aa is 2/4 or 1/2
The probability of Bb to come from a cross between Bb and Bb is 2/4 or 1/2
The probability of Cc to come from a cross between Cc and Cc is 2/4 or 1/2
So the collective probability of AaBbCc offspring from a cross between AaBbCc and AaBbCc parents would be=
1/2 * 1/2 * 1/2 = 1/8
Hence, assuming no effects of the environment, 1/8 of the offspring will have the same fruit color phenotype as the trihybrid parent.
Answer:
How can examining specimens under a microscope help scientists classify an organism? It can help scientists classify an organism because they can see it super close up. In plant cells, how are chloroplasts and mitochondria related?
Explanation:
In prokaryotes the 5' UTR is 3-10 nucleotides.
In Eukaryotes the 5'UTR is 100 to many thousand nucleotides long.
Explanation:
Leader sequence or 5' UTR starts at transcription site and ends at the initiation codon just one nucleotide away from it.
It is present in mRNA.
These are GC rich and form secondary structure, helps in protein synthesis.
Shine Dalgarno sequence in prokaryotes is an example of 5'UTR.
It acts as an entry point of ribosome.
