Answer: 10.79×10^-5 m^2
Explanation:
v2 = 0.94m/s
Cross sectional area(A) = 2 × 10^-4m^2
v1A1 = v2A2 (continuity equation used to compare any two points of the flow of an incompressible fluid. )
A1 = (v2A2) ÷ v1
v1^2 = v2^2 + 2as
v1 = sqrt(v2^2 + 2as)
distance below faucet(s) = 0.11m
Acceleration during to gravity (a) = 9.8m/s^2
Substituting v1 into the continuity equation :
A1 = (v2A2) ÷ sqrt(v2^2 + 2as)
v2A2 = 0.94 × 2 × 10^-4m^2 = 1.88×10^-4
sqrt(0.94^2m/s + (2×9.8m/s^2×0.11m)) =
sqrt(0.8836 + 2.156) = 1.743
A1 = (1.88×10^-4)÷1.743
A1 = 0.000188 ÷ 1.743
A1 = 10.79×10^-5 m^2
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Answer:
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Russia and Japan hoped it help =)
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