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Aleksandr [31]
3 years ago
12

Which angle is supplementary to

Mathematics
1 answer:
Yuri [45]3 years ago
6 0

Answer:

CFD

Step-by-step explanation:

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Number 8 pls giving brainlyist
Gekata [30.6K]

Answer:

the option number 4

Step-by-step explanation:

Hi love,

so the first step is to subtract

4/3x+7=-5

4/3x=-5-7

4/3x=-12

6 0
4 years ago
Read 2 more answers
Jane invested her savings in two investment funds. The amount she invested in Fund A was $6000 less than the amount she invested
Irina18 [472]

Answer:

Jane invested $37,000 in Fund B.

Step-by-step explanation:

Let;

IA = Amount invested in Fund A = $6,000

IB = Amount invested in Fund B = ?

PA = Amount of profit from Fund A = IA * 8% = $6,000 * 8% = $480

PB = Amount of profit from Fund B = IB * 2%

Therefore, we have:

Total profit = PA + PB = $1220 ........................ (1)

Substitute the relevant values into equation (1) and solve for IB, we have:

$480 + (IB * 2%) = $1220

IB * 2% = $1220 - $480

IB * 2% = 740

IB = 740 / 2%

IB = $37,000

Therefor, Jane invested $37,000 in Fund B.

4 0
3 years ago
F(x)=2x and g(x)=2(x−4) .<br> What transformation occurs from function f to function g
Gennadij [26K]
The transformation is that g(x) is 8 less than f(x), considering you must distribute.

g(x)=2(x-4)
g(x)=2x-8
7 0
3 years ago
Read 2 more answers
Which of the following expressions is equal to -3x2 +27?
Pachacha [2.7K]

Answer:

its B or C

Step-by-step explanation:

8 0
3 years ago
Evidencia de aprendizaje Se desea obtener 80 kilogramos de café molido mezclando café arábico de S/18 el kilogramo y café torrad
SIZIF [17.4K]

Answer:

50kg de café torrado

30kg de café arábico

Step-by-step explanation:

Queremos obtener un total de 80kg de café molido.

Se utilizarán:

Café arábico, que cuesta $18 el kg

Café torrado, que cuesta $10 el kg

Queremos que el precio, por kilo, de la mezcla de 80kg sea $13.

Ok, primero debemos definir las variables:

Definamos:

x = cantidad de café arábico usado

y = cantidad de café torrado usado.

Entonces, como la mezcla deberá tener 80kg en total, tenemos:

x + y = 80kg

Y el costo total de esta mezcla será:

x*$18 + y*$10

Si lo dividimos por el peso total, tendremos el costo por kilo, que es:

(x*$18 + y*$10)/80kg

Y queremos que esto sea igual a $13, entonces tenemos la ecuación

(x*$18 + y*$10)/80kg = $13

Ok, ahora tenemos dos ecuaciones, es decir, tenemos un sistema de ecuaciones:

x + y = 80kg

(x*$18 + y*$10) = $13*80kg

(donde reescribimos levemente la segunda ecuación)

Ok, para resolver este sistema trataremos de reemplazar variables, para ello, el primer paso es aislar una de las variables en una de las ecuaciones.

Aislemos x en la primera:

x = 80kg - y

Ahora reemplazamos esto en la otra ecuación:

(x*$18 + y*$10) = $13*80kg

(( 80kg - y)*$18 + y*$10) = $13*80kg

Ahora podemos resolver esto para la variable y:

$18*80kg - $18*y + $10*y = $13*80kg

$18*80kg - $13*80kg = $18*y - $10*y

($18 - $13)*80kg = ($18 - $10)*y

$5*80kg = $8*y

($5*80kg)/$8 = y

50kg = y

Se usan 50kg de café torrado.

y como:

x + y = 80kg

x = 80kg - y

x = 80kg - 50kg = 30kg

Entonces los 30kg restantes serán de café arábico.

y la estrategia utilizada fue el remplazo de variables.

6 0
3 years ago
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