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Paha777 [63]
3 years ago
9

Percent composition identifies the amount (in percent) of each element present in a compound.

Chemistry
1 answer:
bagirrra123 [75]3 years ago
8 0

I believe the answer you are looking for is TRUE!

Forgive me if I am incorrect, hope I helped you out!

Have a great day.

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Write the electron configuration for Br- and state the number of valence electrons. Select one:
Aleks04 [339]

Answer:

1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^62} 4s^{2} 3d^{10} 4p^{5} with 7 valence electrons.

Explanation:

Bromine has 7 unpaired (valence) electrons in its outer shell, and a total of 35 elecrons. Its <em>4s</em> orbital is completely filled with 2 electrons.

The closest answer from the options would be option D.

I hope this helps.

3 0
3 years ago
Which of the following properties of water allows an insect to walk on water?
topjm [15]

adhesion is the correct answer

adhesion is the action or process of adhering to a surface or object.

7 0
3 years ago
What is harder to pull apart a sodium ion from a chloride ion or a potassium ion from a chloride ion?
madreJ [45]
<span>Hydrogen ion, strictly, the nucleus of a hydrogen atom separated from its accompanying electron. Thehydrogen nucleus is made up of a particle carrying a unit positive electric charge, called a proton. The isolated hydrogen ion, represented by the symbol H +, is therefore customarily used to represent aproton.</span><span>
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6 0
4 years ago
H2 H2O H2O2 CH4 All four examples represent
miv72 [106K]
It is covalent  bonds
8 0
3 years ago
Read 2 more answers
How many grams of NaF form when 0.589 mol of HF react with excess Na2SiO3?
BartSMP [9]

Answer:

6.18 g

Explanation:

We know we will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

M_r:                                             41.99  

                 Na₂SiO₃ + 8HF ⟶ 2NaF + H₂SiF₆ + 3H₂O  

<em>n</em>/mol:                         0.58    

1. Use the molar ratio of NaF:HF to calculate the moles of NaF.

\text{Moles of NaF} = \text{0.589 mol HF} \times \frac{\text{2 mol NaF}}{\text{8 mol HF}} = \text{0.1472 mol NaF}

2. Use the molar mass of NaF to calculate the mass of NaF.

\text{Mass of NaF} = \text{0.1472 mol NaF} \times \frac{\text{41.99 g NaF}}{\text{1 mol NaF}} = \text{6.18 g NaF}

8 0
3 years ago
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