<span>Ca(NO3)2 (aq) + Na2SO4 (aq) --> CaSO4 (s) + 2NaNO3 (aq)
Ca2+ (aq) + 2NO3- (aq) + 2 Na+ (aq) + SO4 (aq) --> CaSO4 (s) + 2Na+ (aq) + 2NO3- (aq)
cancel out spectator ions
Ca2+ (aq) + SO4 (aq) ---> CaSO4 (s hope it helps</span>
Answer:
I believe the answer is Molten
Explanation:
I did that quiz and got 100% :)
Answer:
0.444 mol/L
Explanation:
First step is to find the number of moles of oxalic acid.
n(oxalic acid) = 
Now use the molar ratio to find how many moles of NaOH would be required to neutralize
of oxalic acid.
n(oxalic acid): n(potassium hydroxide)
1 : 2 (we get this from the balanced equation)
: x
x = 0.0111 mol
Now to calculate what concentration of KOH that would be in 25 mL of water:

Answer:
To answer your question use the code ICE on here to get your answer works every time for me hope this helps