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faltersainse [42]
2 years ago
14

How many liters are needed to make a 4. 8M solution of KBr if 4 mole of KBr are available for use?

Chemistry
1 answer:
Inessa [10]2 years ago
4 0

4.8 M = \frac{4 mol}{x}

x = 0.83 L

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Al calentar la mantequilla, esta se transforma en liquido, este cambio se denomina?
BlackZzzverrR [31]

Answer:

cambio fisico

Explanation:

4 0
2 years ago
Protons, neutrons, and electrons.
natima [27]
What are you asking?

8 0
3 years ago
Please help ASAP!! <br><br>I am not sure how to solve this! <br><br>​
umka2103 [35]

Answer:

Potassium (K) has 19 protons.

Each neutral atom of Potassium has 19 electrons.

Explanation:

A) Potassium has 19 protons because the atomic number tells us how many protons are in an atom of the element. (The atomic number is the number above the element symbol. For example, the number above "K" is 19, which is the atomic number).

B) If an atom is neutral, this means that the atom has neutral energy. Protons give positive energy and electrons give negative energy. For the atom to be neutral, the atom must have balanced energy, therefore, making the number of electrons equal to the number of protons in a neutral atom.

7 0
3 years ago
How many molecules of co2 in 97.3 grams of co2
s2008m [1.1K]

Answer:

1.33 × 10²⁴ molecules CO₂

General Formulas and Concepts:

<u>Chemistry - Stoichiometry</u>

  • Reading a Periodic Table
  • Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

97.3 g CO₂

<u>Step 2: Define conversions</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

97.3 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} ) = 1.33138 × 10²⁴ molecules CO₂

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules.</em>

1.33138 × 10²⁴ molecules CO₂ ≈ 1.33 × 10²⁴ molecules CO₂

8 0
2 years ago
Compute the reactance of a 0.450 H inductor at the frequency of 60.0 Hz. Express your answer in ohms.
vlada-n [284]

Answer:

169.67Ω

Explanation:

This question is asking for the inductive reactance, which is calculated as follows:

X(L) = 2πfL

Where;

X(L) = inductive reactance (Ω)

f = frequency (Hz)

π = 3.142

L = inductance (Henry)

Given the information provided, f = 60Hz, L = 0.450H

X(L) = 2πfL

X(L) = 2 × 3.142 × 60 × 0.450

X(L) = 6.284 × 60 × 0.450

X(L) = 6.284 × 27

X(L) = 169.668

X(L) = 169.67Ω

7 0
3 years ago
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