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lawyer [7]
3 years ago
11

Which is an example of an incremental approach to solving a problem? writing the program code of the solution informally represe

nting the steps of a solution in a flowchart representing the code of the solution in different programming languages writing the steps of a solution in small pieces of code
Mathematics
1 answer:
Setler [38]3 years ago
4 0

Answer:

writing the steps of a solution in small pieces of code

Step-by-step explanation:

edg 2020

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How do I solve tan(62) = 12/x?
notsponge [240]

Answer:

x = 6/31 = 0.194

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (62)-(12/x)=0

Step by step solution :

Step  1  :

           12

Simplify   ——

           x

Equation at the end of step  1  :

       12

 62 -  ——  = 0

       x

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  x  as the denominator :

          62     62 • x

    62 =  ——  =  ——————

          1        x  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

62 • x - (12)     62x - 12

—————————————  =  ————————

      x              x    

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :

  62x - 12  =   2 • (31x - 6)

Equation at the end of step  3  :

 2 • (31x - 6)

 —————————————  = 0

       x      

Step  4  :

When a fraction equals zero :

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 2•(31x-6)

 ————————— • x = 0 • x

     x    

Now, on the left hand side, the  x  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  2  •  (31x-6)  = 0

Equations which are never true :

4.2      Solve :    2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

4.3      Solve  :    31x-6 = 0

Add  6  to both sides of the equation :

                     31x = 6

Divide both sides of the equation by 31:

                    x = 6/31 = 0.194

Answer :

                  x = 6/31 = 0.194

Rate?

3 0
3 years ago
Any one help with a step by step answer so I can write notes for future reference when working out similar questions? I need hel
max2010maxim [7]

Answer:

<em>Volume = ( About ) 2406.165 cm^3</em>

Step-by-step explanation:

If you consider a cube or a rectangular prism, you could identify it's volume through the multiplication of it's Base by height. A pyramid has 1 / 3rd that volume, so in order to take a volume of the figure to the left, we would multiply Base * height and take 1 / 3rd of that;

Square Pyramid,\\Base ( Square ) = a^2, a = length = 17.2 cm\\Height = 24.4 cm\\\\Volume = 1 / 3 ( Base ) ( Height ),\\Volume = 1 / 3 ( ( 17.2 )^2 )( 24.4 ),\\Volume = 1 / 3( 295.84 )( 24.4 ),\\\\Volume = 98.6133333333( 24.4 ),\\Volume = 2406.16533333,\\\\Volume = ( About ) 2406.165

<em>Solution ⇒ ( About ) 2406.165 cm^3</em>

<em />

Hope that helps!

3 0
3 years ago
Simplest form<br> 3/10 + 7/12 =
pochemuha
3(12)/10(12) + 7(10)/12(10) = 36/120 + 70/120

==> 18/60 + 35/60 = 53/60
7 0
3 years ago
ur a HS photographer taking pictures fir 2 classes of 21 students each. on average, each individual pic takes 3 minutes and a cl
goblinko [34]
2 classes of 21 students each
21 × 2 classes = 42 students in total
42 × 3 mins = 126 minutes for 42 students
10 mins for 2 class pics = 20 minutes
126 + 20 = 146 minutes = 2 hours and 26 minutes

It should take 146 minutes (2 hours and 26 minutes) to take all the pictures.
6 0
3 years ago
forty eight students were divided into two groups for a field trip. The first group is three times as large as the second group
NISA [10]
I believe the first group would have 36 and the second group would have 12
4 0
3 years ago
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