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Hi there!

We are given the equation:
x² - 2y = 7
To verify if each ordered pair is apart of the function, we can plug in their respective x and y values:
1. (5)² - 2(8) = 7
25 - 16 = 9 ≠ 7. This is NOT correct.
2. (-1)² - 2(-3) = 7
1 + 6 = 7. This is correct.
3. (-4)² - 2(-11.5) = 7
16 + 23 = 39 ≠ 7. This is NOT correct.
4. (1.2)² - 2(-2.78) = 7
1.44 +5.56 = 7. This is correct.
Thus, only 1 and 4 are the correct answers.
24+8 = 30
30 - 12 = 18
18-9 = 8
There are 8 cards left in the stack
Answer:
-43
Step-by-step explanation:
-35 + 7 + (-15)
-35 + 7 - 15
-50 + 7
<u>= -43</u>
Answer:
The factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....
Step-by-step explanation:
The given expression is:
2q²-5pq-2q+5p
Make a pair of first two terms and last two terms:
(2q²-5pq) - (2q-5p)
Now factor out the common factor from each group.
Note that there is no common factor in second group. So we will take 1 as a common factor.
q(2q-5p) -1(2q-5p)
Now factor the polynomial by factoring out the G.C.F, 2q-5p
(2q-5p) (q-1)
Thus the factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....