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Alex
3 years ago
12

What formula would you use to calculate the mass of fermium-253 remaining after d days? f(d)=400(0.833)d f(d)=400(0.794)d f(d)=4

00(0.500)d f(d)=400(0.100)d
Mathematics
1 answer:
seraphim [82]3 years ago
4 0

Answer:

f(d)=400(0.794)^d

Step-by-step explanation:

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Write the direct variation function given that y varies directly with x, and y = 16 when x = 4.
Otrada [13]

Answer:

Very little information is given, leaving room to multiple possible functions, however i would expect it to be y = 4x

Step-by-step explanation:

x * z = y

4 * z = 16

z = 16/4

z = 4

5 0
3 years ago
Pls I’m about to cry...
marissa [1.9K]

FORMULA:

  • Volume of cylinder = πr²h
  • Volume of sphere = 4/3πr³

ANSWER:

Volume of capsule = 4/3πr³ + πr²h

πr²(4/3r + h)

  • 3.14 × 2²(8/3 + 5.6)
  • 3.14 × 4(2.6 + 5.6)
  • 12.56(8.2)
  • 102.99 or 103 rounded.

Now, Density = 0.7mg/mm³

  • 0.7/103
  • 0.00679mg

7 0
2 years ago
24 percent of the swim team members are new on the team. how many members are new?
SpyIntel [72]

Answer:

24/100 x 25 =6

Step-by-step explanation:

6 0
3 years ago
After heating up in a teapot, a cup of hot water is poured at a temperature of 204°F.
laila [671]

Answer:

  • Question 1: 0.081 min⁻¹
  • Question 2: 168ºF

Explanation:

The missing equation is:

             T=T_a+(T_0-T_a)e^{-kt}

You are given:

  • Ta = the temperature surrounding the object = 73ºF
  • T₀ = the initial temperature of the object = 204ºF
  • t = 2.5 min
  • T after 2.5 min = 180ºF

Question 1: Find the the value of k.

Substitute the data into the equation and solve for k:

          180\º=73\º+(204\º-73\º)e^{-k\cdot 2.5min}\\ \\ 107\º=131\ºe^{-k\cdot 2.5min}\\\\-k\cdot 2.5min=\ln (107/131)\\\\k=0.081min^{-1}

Question 2: Find the Fahrenheit temperature of the cup of water, to the nearest degree, after 4 minutes.

Subsititute into the formula and compute:

            T=73\ºF+(204\ºF-73\ºF)e^{-0.081min^{-1}\times 4min}\\ \\ T=73\ºF+(131\ºF)(0.72325024)\\\\T=168\ºF

4 0
3 years ago
Find each function value.
Levart [38]

Put the values of x to the equations of the functions:

1. f(9) → x = 9; f(x) = -3x + 10

f(9) = -3(9) + 10 = -27 + 10 = -17

2. f(-2) → x = -2; f(x) = 4x - 1

f(-2) = 4(-2) - 1 = -8 - 1 = -9

3. f(-5) → x = -5; f(x) = -2x + 8

f(-5) = -2(-5) + 8 = 10 + 8 = 18

5 0
3 years ago
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