No less than or greater than signs are used, so C and D are out
In this case the equation starts as .45M + 3.50
The only matching statement is A
Answer:
The Given situation is In 2005, the shabelle river in Somalia rose an estimated 5.25 inches every hour for 15 hours.
Increase in water level is represented by the function,f(x)=5.25 x.
or replacing f(x) by y we get ,y= 5.25 x
This is equation of straight line passing through the origin.
As x is number of hours , so x> 0,(0,∞] Which is it's domain.
As x> 0, so Range is those values of y for which x is defined.
,So Range is y>0 i.e (0,∞}
As the function has no breaking point , that is when you plot the graph on coordinate axis there is no breaking point.So , it is everywhere continuous i. e for all values of x.
The half-life of the given exponential function is of 346.57 years.
<h3>What is the half-life of an exponential function?</h3>
It is the value of t when A(t) = 0.5A(0).
In this problem, the equation is:
.
In which t is measured in years.
Hence the half-life is found as follows:





t = 346.57 years.
More can be learned about exponential functions at brainly.com/question/25537936
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Part 1) <span>In triangle PQR, mP= 43, PQ=7.5 and PR= 8.4. What is mR to the nearest degree?
we know that
the law of cosines establishes that
c</span>²=a²+b²-2*a*b*cos C
in this problem
c=QR
a=PQ=7.5
b=PR=8.4
C=angle P=43°
c²=a²+b²-2*a*b*cos C----> c²=7.5²+8.4²-2*7.5*8.4*cos 43°
c²=34.66--------> c=5.89
QR=5.9
applying the law of sines
7.5/sin R=5.9/sin 43-----> 7.5*sin 43=5.9*sin R---> sin R=7.5*sin 43/5.9
sin R=0.8669---------> R=arc sin (0.8669)----> R=60.11°----> R=60°
the answer Part 1) is the option
<span>D. 60
</span>
Part 2) <span>In triangle ABC mA=43, mB=62 and BC=22 in. What is AB to the nearest tenth of an inch?
we know that
</span>∠C=180-(62+43)-----> ∠C=75°
<span>
Applying the law of sines
22/sin 43=AB/sin 75------> AB=22*sin 75/ sin 43-----> AB=31.16 in
AB=31.2 in
the answer Part 2) is
</span><span>D.31.2</span>
Answer:
-ad-r=C
-------- Sorry thats the best I could do for a fraction symbol
3-b
Step-by-step explanation:
In order to solve for C we need to get it C on one side of the equation all by itself. To start we can subtract R from both sides and subtract bc from both sides to get both C's on one side. That gets us to
-ad-r=3c-bc
Since the side with C has a common factor, C between 3c and bc we can pull that out, and we get
-ad-r=c(3-b)
and then we just divide 3-b on both sides to get C completely by itself
-ad-r=C
--------
3-b
I hope this helps and please don't hesitate to ask if there is anything still unclear!