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Olegator [25]
3 years ago
9

I need help with math if you don't know the answer get out of the question and don't answer it and give the wrong answer or some

link or even say "I don't know" or anything like that it's not fair to me cause it a waste of my points I will report your if you do that :) have a nice day and stay safe

Mathematics
1 answer:
Law Incorporation [45]3 years ago
3 0

Answer:

13 1/3 pounds

Step-by-step explanation:

Hi! Each bad weighs 2 2/3 pounds. There were 5 bags bought so we multiply. Here is the expression:

2 2/3 x 5 = x

Now we need to convert 2 2/3 into an improper fraction, which is 8/3.

Easy! Now

8          5         40

-      x    -     =    -

3           1          3

*I tried to set it up like fractions.*

Simplify 40/3 and you get 13 1/3

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Drag the tiles to the boxes to form correct pairs.
FrozenT [24]

Answer:

1 .4x2-9= 2x+3,2x-3

2 .16x2-1=4x-1,4x+1

3 .16x2-4=4(2x+1)(2x-1)

4 .4x2-1=(2x+1)(2x-1)

Step-by-step explanation:

16x² − 1  = (4x − 1)(4x + 1) ;  16x² − 4  = 4(2x + 1)(2x − 1); 4x² − 1  = (2x + 1)(2x − 1) ;

4x² − 9 = (2x + 3)(2x − 3)

16x² − 1  is the difference of squares.  This is because 16x² is a perfect square, as is 1.  To find the factors of the difference of squares, take the square root of each square; one factor will be the sum of these and the other will be the difference.

The square root of 16x² is 4x and the square root of 1 is 1; this gives us (4x-1)(4x+1).

16x² − 4 is also the difference of squares.  The difference of 16x² is 4x and the square root of 4 is 2; this gives us (4x-2)(4x+2).  However, we can also factor a 2 out of each of these binomials; this gives us

2(2x-1)(2)(2x+1) = 2(2)(2x-1)(2x+1) = 4(2x-1)(2x+1)

4x² − 1  is also the difference of squares.  The square root of 4x² is 2x and the square root of 1 is 1; this gives us (2x-1)(2x+1).

4x² − 9 is also the difference of squares.  The square root of 4x² is 2x and the square root of 9 is 3; this gives us (2x-3)(2x+3).

3 0
3 years ago
If u, v, and w are nonzero vectors in r 2 , is w a linear combination of u and v?
Tju [1.3M]
Not necessarily. \mathbf u and \mathbf v may be linearly dependent, so that their span forms a subspace of \mathbb R^2 that does not contain every vector in \mathbb R^2.

For example, we could have \mathbf u=(0,1) and \mathbf v=(0,-1). Any vector \mathbf w of the form (r,0), where r\neq0, is impossible to obtain as a linear combination of these \mathbf u and \mathbf v, since

c_1\mathbf u+c_2\mathbf v=(0,c_1)+(0,-c_2)=(0,c_1-c_2)\neq(r,0)

unless r=0 and c_1=c_2.
8 0
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Hi can anyone help with this I'm really tired ngl<br><br>What is the area of the hexagon
laila [671]

Answer:

371.2

Step-by-step explanation:

5 0
3 years ago
what is the common denominator of 1 / a + 1 / B in the complex fraction 1 / a - 1 / B / 1 / 8 + 1 / B​
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Answer:

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3 years ago
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Find the average.<br><br> 11,16,15,22<br><br> A.64<br> B.15<br> C.17<br> D.16
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