Please help me I just want to finish this so I can go to sleep.

Mathematics

2 answers:

Daniel [21]2 years ago

7 0

Answer:

3rd and 6th

Step-by-step explanation:

nikdorinn [45]2 years ago

6 0

The third and last options are the answers.
The graph is shifted to the right by some number. The coordinates aren't numbered, so it could be literally anything. To shift to the right, the equation will be |x-y| where y is any number.

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Please help me ASAP!!! Will give brainlist:))

trasher [3.6K]

Answer:

I think it is D

Step-by-step explanation:

I am guessing because the stem should be 5 for sure but I am not so sure about my answer it leaves you with one of the choices with the number 5 in them.

I hoped I kinda helped if I didn't I am so sorry :(

5 0

2 years ago

A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the populati

Marysya12 [62]

The $100(1-\alpha)\%$ confidence interval of a standard deviation is given by:

$\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}$

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval,

$\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493$

Therefore, the 90% confidence interval for the standard deviation is given by

$\sqrt{ \frac{(31-1)50^2}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(31-1)50^2}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{(30)2500}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(30)2500}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{75000}{43.773 }} \leq\sigma\leq\sqrt{ \frac{75000}{18.493 }} \\ \\ \Rightarrow \sqrt{1713.38} \leq\sigma\leq \sqrt{4055.59} \\ \\ \Rightarrow41.4\leq\sigma\leq63.7$

3 0

2 years ago

Solve the problem below and enter your answer in the space below <br> 7x (3-2) = ?

postnew [5]

Answer:

Step-by-step explanation:

PEMDAS

3-2=1

5 0

3 years ago

F(x)=2(3-x),find f(-7)

Sauron [17]