Step-by-step explanation:
Hey there!
<u>Firstly </u><u>find </u><u>slope </u><u>of</u><u> the</u><u> </u><u>given</u><u> equation</u><u>.</u>
Given eqaution is: 3x + 2y = 5.......(i)
Now;
Therefore, slope (m1) = -3/2.
As per the condition of parallel lines,
Slope of the 1st eqaution (m1) = Slope of the 2nd eqaution (m2) = -3/2.
The point is; (-2,-3). From the above solution we know that the slope is (-3/2). So, the eqaution of a line which passes through the point (-2,-3) is;
(y-y1) = m2 (x-x1)
~ Keep all values.
~ Simplify it.
Therefore, the eqaution of the line which passes through the point (-2,-3) and parallel to 3x + 2y= 5 is 3x + 2y +12 =0.
<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Triangle HAM looks like an isosceles triangle, and we know that in an isosceles triangle 2 of the angles are the same.
so :
180 - 106 = 74 ( sum of the other 2 angles )
74/2 = 37 ( sum of angle HMA / HAM )
angles on a straight line add up to 180.
180-37=143 ( angle x )
since triangle YMH is also an isosceles,
180-37=143
143/2=71.5 ( angle w )
Answer:
−3d−5e−2
Step-by-step explanation: