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Semmy [17]
3 years ago
14

Determine the equation of the quadratic function shown below.

Mathematics
1 answer:
makvit [3.9K]3 years ago
4 0

Answer:

d

Step-by-step explanation:

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The cube of twice a number
raketka [301]

Answer:

The cube of twice a number.

Twice a quantity usually indicates to take two of the things in question; usually this indicates to multiply by 2. Thus "twice a number x" can be written symbolically as 2x. If this is part of a problem, say twice a number x is 6, then we can rewrite algebraically as 2x=6; dividing both sides by 2 yields x=3.

Step-by-step explanation:

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3 0
3 years ago
3.5x - 11 = 20.5 what does x equal?
stepan [7]

Answer:

x=9

Step-by-step explanation:

3.5x - 11 = 20.5

Add 11 to each side

3.5x - 11+11 = 20.5+11

3.5x = 31.5

Divide each side by 3.5x

3.5x/3.5 = 31.5/3.5

x =9

7 0
3 years ago
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Work out 6 x £85.20 help please math homework for tomorrow!
Over [174]
I think the. answer is 511.2
6 0
4 years ago
Using the approximation 3.14 for \pi what is the radius of a circle with circumference 75.4m
Charra [1.4K]

Answer:

The radius of the circle is 12.006 m.

Step-by-step explanation:

Let us assume the radius of the circle = r

Circumference  = 75.4 m

Now, CIRCUMFERENCE OF A CIRCLE = 2 π r

⇒ 75 .4 m = 2 π r

Now, putting  π = 3.14, we get:

75 .4 m = 2 (3.14)  r

⇒ 75.4 = 6. 28 r

or, r = 75.4/6.28 =  12.006

or, r  = 12.006 m

Hence, the radius of the circle with circumference 75.4 m is 12.006 m.

3 0
4 years ago
Determine whether the congruence is true or false.<br> 12 ≡ 10 mod 5
dolphi86 [110]

Answer:

The given congruence is false.

Step-by-step explanation:

Given : Expression 12 \equiv 10 \mod 5

To find : Determine whether the congruence is true or false ?

Solution :

The congruence is in the form x\mod y\equiv r

where, x is the dividend

y is divisor

r is the remainder

So, We find  10 \mod 5

We know, 10 is completely divide by 5 and we get quotient is 2 and remainder is 0.

10 \mod 5=0

As 0\neq 12

Therefore, The given congruence is false.

8 0
4 years ago
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