The three scientist are Matthias Schleiden<span>, </span>Theodor Schwann<span>, </span>Rudolph Virchow<span> 4.
Hope it helped!</span>
The correct answer is:
The principal cause of aneuploidy is chromosome nondisjunction during mitosis or meiosis. Polyploidy in nature can result either from the duplication of euploid chromosome sets from a single species or from the combining of chromosome sets from different species.
Aneuploidy is a phenomenon when there is the presence of an abnormal number of chromosomes in a cell (an extra or missing chromosome). Usually it appears as a result of improper cell division (chromosomes don’t separate) and it can cause many genetic disorders.
Polyploidy refers to a state when there are more than two sets of chromosomes (one from mother one from father). Triploid (three sets of chromosomes) and tetraploid (four sets of chromosomes) chromosomes are examples of polyploidy. This phenomenon is most common in plants.
From a modern genetic perspective, this is defined as evolution.
Answer:
TRANSCRIPTION
Explanation:
Transcription is the first process that occurs in the expression of a gene. It involves the synthesis of a mRNA molecule from a DNA template. The DNA molecule, which is located in the nucleus of an eukaryotic cell, is bound to by an enzyme called RNA polymerase in order to synthesize an mRNA molecule/strand.
RNA polymerase synthesizes a mRNA molecule using complementary base pairing rule i.e. Uracil base (U) is synthesized when Adenine (A) is read, Adenine when Thymine (T) is read, Guanine (G) when cytosine (C) is read, Cytosine when guanine is read. These nucleotide bases are then joined together via chemical bonding.
In a nutshell, RNA polymerase catalyzes the formation of a bond between the backbone sugar of one nucleotide base to the backbone phosphate of another nucleotide base in the metabolic process of TRANSCRIPTION.
The answer is 9%.
To calculate this we will use some <span>formulas of the Hardy-Weinberg principle:
</span><span>p² + 2pq + q² = 1 and <span>p + q = 1
where:
</span></span>
<span>p - the frequency of the A allele.
q - the frequency of the a allele.</span>
p² - the frequency of dominant homozygote (with AA genotype)
2pq - the frequency of heterozygote (with Aa genotype)
<span>q² - the frequency of recessive homozygote (with aa genotype)</span>
<span>We know:</span>
p = 70% = 70/100 = 0.7
q = 30% = 30/100 = 0.3
We need to calculate the frequency of the genotype aa:
q² = ?
Since we know the frequency of allele q, it is easy to calculate the frequency of the genotype aa:
q² = 0.3² = 0.09 = 0.09 · 100% = 9%
