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3 years ago

If ↔w||↔v, find the measurement of angle a. ∠a =

Mathematics

1 answer:

hram777 [196]3 years ago

6 0

Answer:

the answer is 137 degree s

Step-by-step explanation:

It's the opposite side of it meaning it's on the bottom where is the same

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Find the area of this parallelogram

gulaghasi [49]

Answer:

140 cm²

Step-by-step explanation:

The height of the parallelogram is 10cm . And its base is 14cm .We know that the area of parallelogram is product of base and height .

⇒ Area = base × Height

⇒ Area = 14cm × 10cm

⇒ Area = 140 cm² .

<h3>Hence the area of the parallelogram is 140 cm² .</h3>

7 0

3 years ago

I need help answering this question, Asap

Natasha2012 [34]

Answer:

(-65)/17

Step-by-step explanation:

Evaluate 3/(x - 2) - sqrt(x - 3) where x = 19:

3/(x - 2) - sqrt(x - 3) = 3/(19 - 2) - sqrt(19 - 3)

19 - 3 = 16:

3/(19 - 2) - sqrt(16)

19 - 2 = 17:

3/17 - sqrt(16)

sqrt(16) = sqrt(2^4) = 2^2:

3/17 - 2^2

2^2 = 4:

3/17 - 4

Put 3/17 - 4 over the common denominator 17. 3/17 - 4 = 3/17 + (17 (-4))/17:

3/17 - (4×17)/17

17 (-4) = -68:

3/17 + (-68)/17

3/17 - 68/17 = (3 - 68)/17:

(3 - 68)/17

3 - 68 = -65:

Answer: (-65)/17

4 0

3 years ago

Read 2 more answers

URGENT: If θ is a second-quadrant angle and cosθ = -2/3, then tanθ = _____.

dangina [55]

In the second quadrant, both cos and tan are negative while only sin is positive.

To find tan, we will use the following property below:

$\large \boxed{ {tan}^{2} \theta = {sec}^{2} \theta - 1}$

Sec is the reciprocal of cos. If cos is a/b then sec is b/a. Since cos is 2/3 then sec is 3/2

$\large{ {tan}^{2} \theta = {( - \frac{3}{2}) }^{2} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - \frac{4}{4} \longrightarrow \frac{5}{4} } \\ \large{tan \theta = \frac{ \sqrt{5} }{ \sqrt{4} } } \\ \large \boxed{tan \theta = \frac{ \sqrt{5} }{2} }$