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kap26 [50]
3 years ago
12

How many solutions does 4(x-1)=4x+5

Mathematics
2 answers:
sergeinik [125]3 years ago
6 0

Answer:

NO SOLUTION

Step-by-step explanation:

To solve this problem, first you have to isolate it on one side of the equation.

First, expand.

\displaystyle 4(x-1)=4x-4

\displaystyle 4x-4=4x+5

Next, add 4 from both sides.

\displaystyle 4x-4+4=4x+5+4

Solve.

\displaystyle 4+5=9

\displaystyle 4x=4x+9

Subtract 4x from both sides.

\displaystyle 4x-4x=4x+9-4x

Solve.

\displaystyle 0=9

Therefore, there are no solution.

mihalych1998 [28]3 years ago
3 0

4(x - 1) = 4x + 5

Eliminate parentheses on the left:

4x - 4 = 4x + 5

Subtract 4x from each side:

-4 = +5

No value of x can make this a true statement. So no solution exists.

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