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3 years ago

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a total of $67,000 is to be invested, some bonds and some in certificates of deposit (CDs). If the amount in bonds is to exceed

that in CDs by $5,000, how much will be invested in each type of investment ?

1 answer:

Semmy [17]3 years ago

5 0

First you have to divide then you have to multiply your answer with the original answer then

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What is the sum of -2/3 and -4/6? i just want the answer

ddd [48]

Answer: A

Step-by-step explanation:

-2/3+(-4/6)

= -2/3 -2/3

=(-2-2)/3

=-4/3

3 0

3 years ago

Solve by factoring.<br><br> 1.) 0=6x^2-13x-5<br><br> 2.) 0=4x^2-7x+3

s2008m [1.1K]

1. x= -1/3 or x= 5/2

2. x=3/4 or x=1

6 0

3 years ago

The choices are:

Harrizon [31]

Let's take a look at D:

<span>D) y = (x-1)^2 - 16 Compare this to
y = (x-h)^2 + k This is the std. equation of a parabola in vertex form.

You can see, by comparison, that h=1 and k= -16; these are the coordinates of the vertex, clearly shown in the diagram.

Since the coefficient of (x-h)^2 is +1, the graph opens upward (which the given graph confirms), and is neither compressed nor stretched vertically.</span>

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4 years ago

The net worthw(t) of a company is growing at a rate of′(t) = 2000−121t2dollarsper year, wheretis in years since 1990.(a) If the

stiv31 [10]

Answer:

The worth of the company in 2000 is $56,000.

Step-by-step explanation:

The growth rate of the company is:

$f'(t)=2000-12t^{2}$

To determine the worth of the company in 2000, first compute the change in the net worth during the period 1990 (<em>t</em> = 0) to 2000 (<em>t</em> = 10) as follows:

$\int\limits^{10}_{0} {2000-12t^{2}} \, dt =\int\limits^{10}_{0} {2000} \, dt-12\int\limits^{10}_{0} {t^{2}} \, dt=2000 |t|^{10}_{0}-12|\frac{t^{3}}{3}|^{10}_{0}\\=(2000\times10)-(4\times10^{3})\\=20000-4000\\=16000$

The increase in the company's net worth from 1990 to 2000 is $16,000.

If the company's worth was $40,000 in 1990 then the worth of the company in 2000 is:

Worth in 2000 = Worth in 1990 + Net increase in company's worth

$=40000+16000\\=56000$

Thus, the worth of the company in 2000 is $56,000.

4 0

3 years ago

There are 874 pieces of candy in the piñata. There are 23 children at the party, and they all agreed to split the candy equally.

blsea [12.9K]

Answer:

38 candies.

Step-by-step explanation:

Given the following data;

Total number of candy = 874

Total number of children = 23

Since we know that they are all sharing it equally, each child would get;

Each child = 874/23

Each child = 38 candies.

6 0

3 years ago