$7( \sqrt[3]{2x} ) - 3( \sqrt[3]{16x} ) - 3( \sqrt[3]{8x} ) \\ = 7 \sqrt[3]{2x} - 3 \times ( \sqrt[3]{2 \times 2 \times 2 \times 2x} - 3 \times \sqrt[3]{2 \times 2 \times 2x} \\ = 7 \sqrt[3]{2x} - 3 \times (2 \sqrt[3]{2} x) - 3 \times 2x \\ = 7 \sqrt[3]{2x} - 3 \times 2 \times \sqrt[3]{2x} - 3 \times 2x \\ = 7 \sqrt[3]{2x} - 6 \sqrt[3]{2x} - 6x$

Hope this helps...

Good luck on your assignment...

7 0

3 years ago

The price of a gallon of gasoline is 3.16 the price when Ryan’s mother started driving was 1/4 of the current price what was the

jenyasd209 [6]

"of" means multiply, "was/is" means equals

started driving price was 1/4 of current price

? = 1/4 x 3.16

? = 3.16/4

? = .89

Answer: $0.89

8 0

3 years ago