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Marta_Voda [28]
3 years ago
7

Which operation should be used to solve this problem?

Mathematics
1 answer:
Blizzard [7]3 years ago
7 0
A and b is how to get the answer
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how do you have a reflection in the x axis, if the shape is already partially in the third and second quadrent of the graph
IgorLugansk [536]

Its a reflection over an x-axis, whats "positive" goes "negative" and whats "negative" goes "positive" with respect to y.

If a shape S is a subset (made of P_2\cup P_3 of quadrants Q_2,Q_3 then the part P_2 that lies in the second quadrant gets mapped to Q_3 and part P_3 that lies in third quadrant gets mapped to Q_2

Hope this helps.

8 0
3 years ago
Solve for x.<br><br> 4(x + 2) = 48<br><br> x = 6<br> x = 7<br> x = 10<br> x = 14
Mrac [35]

Answer:

x = 10

Step-by-step explanation:

plug and chug using a calculator

4(10+2)

10+2= 12 x 4=48

7 0
3 years ago
What is a graph of a quadratic equation called
Mazyrski [523]

Answer:

Probably a parabola

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
Decide if each expression is equivalent to 2^6 or 4^4
11Alexandr11 [23.1K]

\huge\text{Hey there!}

\mathsf{2^6 = 2\times2\times2\times2\times2\times2}\\\mathsf{2\times2\times2\times2\times2\times2}\\\mathsf{2\times2=4}\\\mathsf{4\times4\times4}\\\mathsf{4\times4=16}\\\large\mathsf{16\times4=64}\\\mathsf{2^6 = \bf{64}}

\mathsf{4^4=4\times4\times4\times4}\\\mathsf{4\times4\times4\times4}\\\mathsf{4\times4=16}\\\mathsf{16\times16}\\\mathsf{16\times16=256}\\\mathsf{4^4=\bf{256}}

\boxed{\boxed{\mathsf{Answer: 64\neq 256}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

6 0
3 years ago
Hhhghjghzhdjdjdiifhjdjdb
beks73 [17]
The third one is the answer but i may be wrong
3 0
3 years ago
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