I think the answer is find it out your dang self LOL #DEEZNUTZ
One example would be x to the power of 1/3
which we would write as x^(1/3) for shorthand
It converts to "cube root of x".
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The general rule is
![x^{1/n} = \sqrt[n]{x}](https://tex.z-dn.net/?f=x%5E%7B1%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%7D)
if the font is too small, then the formula reads x^(1/n) is equal to square root x, with a small little n just above and to the left of the square root. This is known as the nth root of x.
Based on that general formula, we can say something like
![x^{1/4} = \sqrt[4]{x}](https://tex.z-dn.net/?f=x%5E%7B1%2F4%7D%20%3D%20%5Csqrt%5B4%5D%7Bx%7D)
(x to the 1/4th power is equal to fourth root of x)
note: you can replace x with any algebraic expression you want
Answer:
12%
Step-by-step explanation:
calculator
A: {-4, -2 -1, 2}<br>
B: {-4, 4}<br>
C: {-3, -2, 0, 2}<br>
D: {-4, -2, -1, 0, -2}
Temka [501]
Answer:this is soooo compli
Step-by-step explanation:
V=1/2a*c*h this is to solve the volume of a prism