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2 years ago

Help me now !!!!!!!!!!!!!!!!

Mathematics

1 answer:

miskamm [114]2 years ago

3 0

In the first diagram the value of k is 10 and in the second diagram the value of k is 15/2.

<h3>What is the triangle?</h3>

The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.

In the first diagram:

The sum of the 5k + 20 and 7k + 40 is 180

5k + 20 + 7k + 40 = 180

12k + 60 = 180

12k = 180 -60

12k = 120

k = 10

In the second diagram:

The sum of the two interior angles is equal to the exterior angle.

40 + 12k + 10 = 8k + 80

4k = 30

k = 30/4 = 15/2

Thus, in the first diagram the value of k is 10 and in the second diagram the value of k is 15/2.

Learn more about the triangle here:

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Write a linear equation in point-slope form for the line that goes through (1, -3) and (3,9).

dimaraw [331]

The slope of the line is 6, meaning that you can eliminate A,C. Since the point slope formula is y-y1=m(x-x1) you just need to see if the points are correct.

B. (3,9)
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While these do contain one point, substitute the coordinates to see which contain both.

B.

(1,-3): -3-9=6(1-3): -12=-12
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D.

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D is correct since the coordinate are on the line.

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3 years ago

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Gianna uses 100 stamps each day for her business. If she begins each day with 100 stamps, and after each package that is shipped

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Step-by-step explanation:

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3 years ago

Show your work. (x^2 + 2x +3)(x^2 - 2x -2)

Fudgin [204]

I got:
by multiplying each factor....
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4 years ago

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IrinaVladis [17]

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3 years ago

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A 11 gram sample of a substance that’s used to treat thyroid disorders has a k- value of 0.125

NikAS [45]

The substance's half-life is 5.5 days if the 11-gram sample of a substance that’s used to treat thyroid disorders has a k- the value of 0.125

<h3>What is exponential decay?</h3>

During exponential decay, a quantity falls slowly at first before rapidly decreasing. The exponential decay formula is used to calculate population decline and can also be used to calculate half-life.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have an exponential function:

$\rm N = N_oe^{-kt}$

Plug N = N⁰/2

$\rm N_o/2 = N_oe^{-kt}$

$\rm \dfrac{1}{2} = e^{-0.125t}$

Solving for t:

t = 5.54 ≈ 5.5 days

Thus, the substance's half-life is 5.5 days if the 11-gram sample of a substance that’s used to treat thyroid disorders has a k- the value of 0.125

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2 years ago