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Ivanshal [37]
3 years ago
7

How to simplify 27/51

Mathematics
2 answers:
boyakko [2]3 years ago
8 0
Bob the numerator and denominator are divisible by 3 so the simplified fraction would be 9/17
vovikov84 [41]3 years ago
8 0
Cancel the common factors in the numerator and denominator.

Exact Form:
<span>917

</span>Decimal Form:<span>0.52941176<span>…</span></span>
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Answer this equation: 4 3/5 - -3 2/5 + 3
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Answer:

24

Step-by-step explanation:

4\frac{3}{5} -(-3\frac{2}{5})+3

Negative and another negative makes a positive.

4\frac{3}{5}+3\frac{2}{5}+3

Add the fractions first.

7\frac{5}{5}+3

5/5 is equivalent to 1. 7 5/5 becomes 8.

8+3

Add the numbers.

24

I hope this helps!

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52. Kite ABCD has a longer diagonal AC with a length of 20in and a shorter diagonal BD with a length of 15in. The diagonals inte
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7.5
the answer is 7.5
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Jamie painted a small rectangular drawing at
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Answer:

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Step-by-step explanation:

6 0
2 years ago
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A news report states that the 99% confidence interval for the mean number of daily calories consumed by participants in a medica
expeople1 [14]

Answer:

The sample mean is of 1925 calories.

The margin of error is of 75 calories.

The sample standard deviation is of 109.7992 calories.

Step-by-step explanation:

Sample mean:

The sample mean is the mean value of the two bounds of the confidence interval. So

M = \frac{1850 + 2000}{2} = 1925

The sample mean is of 1925 calories.

The margin of error

Difference between the bounds and the sample mean. So

2000 - 1925 = 1925 - 1850 = 75 calories.

The margin of error is of 75 calories.

Sample standard deviation:

Here, I am going to expand on the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 18 - 1 = 17

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 17 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.898

The margin of error is:

M = T\frac{s}{\sqrt{n}}

In which s is the standard deviation of the sample and n is the size of the sample.

Since M = 75, T = 2.898, n = 18

M = T\frac{s}{\sqrt{n}}

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s = \frac{75\sqrt{18}}{2.898}

s = 109.7992

The sample standard deviation is of 109.7992 calories.

6 0
2 years ago
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