Can you post the image of the question?
So there for i can help
a. Let
be a random variable representing the weight of a ball bearing selected at random. We're told that
, so

where
. This probability is approximately

b. Let
be a random variable representing the weight of the
-th ball that is selected, and let
be the mean of these 4 weights,

The sum of normally distributed random variables is a random variable that also follows a normal distribution,

so that

Then

c. Same as (b).
Answer: 7:49
Step-by-step explanation: As you can see in the table, if you divide the number of fans present at a football game by the number of students, you would always get 7. So, 7:49 is a choice because if you divide 49 by 7, you get 7. Hope this helps!!
Hey there!
This can be written as

This is in form of

, it can be expanded as
=> (n-7)(n+7)=0
=> n -7 = 0 or n + 7 = 0
=> n = 7 or n = -7
So option 7 , -7 are correct.
Hope this is clear :)
Have a good day:)
Answer:
Do your school work and stop trying to find answers kid >:( you gonna fail
Step-by-step explanation: